📄 p3181fai.m
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%一般最小二乘方法(引入随机相位)
clear all;
N = 128;
Pi = 3.1415926;
n = [1:1:128];
p=6; %可调AR阶数
q=16;
Times=100; %独立仿真次数
f=zeros(Times,2);
for k=1:Times
w = randn(1,N);
fai1=rand*2*Pi-Pi;
fai2=rand*2*Pi-Pi;
x = sqrt(20)*sin(2*Pi*0.2*n+fai1)+sqrt(2)*sin(2*Pi*0.213*n+fai2)+w;
%r=R(N,x,T) %N is the data number,T is the time delay
Re=zeros(p,p);
for i=1:p
for j=1:p
T=q+1-p+(i-1)+(j-1);
Re(i,j)=R(N,x,T);
end
end
for i=1:p
r(i,1)=-R(N,x,q+i);
end
A=Re;
a1=((A.'*A)^(-1))*(A.')*r;
for i=1:p
a(k,i)=a1(p+1-i);
end
z1=roots([1,a(k,:)]);
z=0;
num=1;
for i=1:p
if 0.95<abs(z1(i))&abs(z1(i))<1.05
z(num)=z1(i);
num=num+1;
end
end
num=1;
for i=1:length(z)
temp=atan(imag(z(i))/real(z(i)))/(2*Pi);
if temp>0
f(k,num)=temp;
num=num+1;
end
end
end
%让f从大到小排序
f=sort(f,2,'descend');
ua=sum(a)/Times;
da=0;
for i=1:Times
da=da+((a(i,:)-ua).^2);
end
da=da/Times;
uf=sum(f)/Times;
df=0;
for i=1:Times
df=df+((f(i,:)-uf).^2);
end
df=df/Times;
ua
da
uf
realf=[0.2 0.213]
temp2=size(f);
realff=zeros(1,temp2(2));
realff(1:2)=[0.2 0.213];
df
offset=abs(realff-uf)
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