connum062cn.c

进制转换程序 不错的啊 各种进制之间互相转换

/* 进制转换程序  ConvertNumber Version 0.6.2 #20060213

 * a Bunki program. Kikistar SoftStyle.
 * All Rights Died, All Freedom Reserved.

 * http://kikistar.com
 * E-mail: [e-mail]

 */

#include <stdio.h>
#include <stdlib.h> /* the strtol(), k&r p252 */
#include <ctype.h>
#include <string.h>

void getindex(int n, char index[]);
int getnumber(char stringin[], int base);
void intton(int numin, int baseout, char numout[]);
void goback(int n);
void printwarn(void);
void showresult(int base);

#define INDEXWIDTH 3 /* two letters and a '\0' */

int main()
{
    int e;
    char index[INDEXWIDTH];
    
    printf("\n");
    printf("进制转换 ConverNumber 0.6.2 #20060213\n");
    printf("---------------------------------------------------\n");
    printf("| 本程序用以对数字进行进制转换。                  |\n");
    printf("|                                                 |\n");
    printf("| 请先选择一种进制，然后输入一个数字，            |\n");
    printf("| 我会把这个数字转换成其它进制数。                |\n");
    printf("---------------------------------------------------\n");

    e = 1;
    while (e == 1) {
	 printf("\n\t\tA. 十进制\t(10)\n");
	 printf("\t\tB. 十六进制\t(16)\n");
	 printf("\t\tC. 八进制\t(8)\n");
	 printf("\t\tD. 二进制\t(2)\n");
	 printf("\n\t\tE. 安全出口\t(0)\n");
	 printf("\n请选择一种进制（然后按回车键）:");

	 getindex(INDEXWIDTH, index);
	 if (strcmp(index,"a")==0||strcmp(index,"A")==0)
	      showresult(10);
	 else if(strcmp(index,"b")==0||strcmp(index,"B")==0)
	      showresult(16);
	 else if(strcmp(index,"c")==0||strcmp(index,"C")==0)
	      showresult(8);
	 else if(strcmp(index,"d")==0||strcmp(index,"D")==0)
	      showresult(2);
	 else if(strcmp(index,"e") == 0
		 || strcmp(index,"E") == 0
		 || strcmp(index,"0") == 0)
	      e = 0;
	 else if ((isdigit(index[0]) && isdigit(index[1]))
		  || (isdigit(index[0]) && index[1] == '\0'))
	 {
	      if (atoi(index) < 2 || atoi(index) > 36){
		   printf("\n\7");
		   printf("\t--------------------------------------\n");
		   printf("\t| Error!                             |\n");
		   printf("\t| 我对不起你，我只能转换2至36进制数。|\n");
		   printf("\t--------------------------------------\n");
	      }
	      else 
		   showresult(atoi(index));
	 }
	 else {
	      printf("\n\7");
	      printf("\t-------------------------------------------------\n");
	      printf("\t| Error!                                        |\n");
	      printf("\t| 请输入一个字母 'a', 'b', 'c', 'd', 或 'e'     |\n");
	      printf("\t| 或者输入一个数字，例如 32（表示三十二进制数） |\n");
	      printf("\t| 然后按回车键。                                |\n");
	      printf("\t-------------------------------------------------\n");
	 }
    }
    printf("\n\t感谢你使用本程序！欢迎来blog来mail交流。\n");
    printf("\thttp://my.opera.com/419/\n");
    printf("\[e-mail]\n\n");
    return 0;
}

void getindex(int width, char index[])
{
     int i;
     char c;

/* 过滤所输入的全部char，记录前n个字符 */ /* k&r p18 */
     for (i=0; (c = getchar()) != '\n'; ++i)
	  if (i < width)
	       index[i] = c;

     index[i] = '\0';
}

void showresult(int base)
{
     int i;
     int numberin;
     char stringin[30];
     char numberout[30];

     printf("\n请输入一个%2d 进制数：", base);
     numberin = getnumber(stringin, base);
     if (numberin < 0)
	  ;
     else {
	  numberin = strtol(stringin, NULL, base);
	  if (numberin == 2147483647){
	       printf("\n\7");
	       printf("\t-------------------------------------\n");
	       printf("\t| 注意！                            |\n");
	       printf("\t| 以下是数字是我能处理的最大数了。  |\n");
	       printf("\t-------------------------------------\n");
	       intton(2147483647, base, stringin);
	  }
	  printf("\n\t\t  %s (%d)\n", stringin, base);
	  for (i = 16; i > 1; i /= 2)
	       if (i == base || i == 4)
		    ;
	       else {
		    intton(numberin, i, numberout);
		    printf("\t\t= %s (%d)\n", numberout, i);
	       }
	  printf("\n");
	  if (base != 10){
	       intton(numberin, 10, numberout);
	       printf("\t\t= %s (10)\n", numberout);
	  }
	  if (base != 36){
	       intton(numberin, 36, numberout);
	       printf("\t\t= %s (36)\n", numberout);
	  }
	  
	  goback(0);
     }
}

int getnumber(char stringin[], int base)
{
     char number[1000];
     char wrong;
     int i, j;

     j = 0;
     for (i=0; ((number[i]=getchar()) != '\n'); ++i)
	  if (base >= 2 && base <= 10) {
	    if (number[i] < '0' || number[i] >= base+'0'){
	      wrong = number[i];
	      j = 1;
	      goback(1);
	      break;
	    }
	  }
	  else if (base >= 11 && base <= 36) {
	       if (isalpha(number[i]) && toupper(number[i]) < base - 10 + 'A')
		    ;
	       else if (isdigit(number[i]))
		    ;
	       else {
		    wrong = number[i];
		    j = 1;
		    goback(1);
		    break;
	       }
	  }
	  else {
	    printf("Error03!\n");
	    printf("Sorry, I can only convert a number base from 2 to 36.");
	  }
     if (j == 1) {
       printf("\n\7");
       printf("\t------------------------------------------\n");
       printf("\t| Error!                                 |\n");
       if (wrong != '.')
	 printf("\t| %2d进制数里没有 '%c'.                    |\n", base, wrong);
       else
         printf("\t| 不好意思啦，我不会转换带小数点的数字   |\n");
       printf("\t|                                        |\n");
       printf("\t| Tips: 不输入数字直接按回车键可回主菜单 |\n");
       printf("\t------------------------------------------\n");
       showresult(base);
       return -1;
     }
     number[i] = '\0';	/* k&r p29, p30 */
     strcpy(stringin, number);
     if (i == 0)
       return -1;
     else 
       return strtol(stringin, NULL, base);
}

/* 算法参考 <<C语言实用程序设计100例>> 人民邮电出版社
 *
 * 本函数把 numin（一个十进制数） 转换成 numout（baseout进制数），
 * baseout的范围是2-36
 *
 * 用函数的参数“返回”数据，k&r Section 1.9 */
void intton(int numin, int baseout, char numout[])
{
    int j, i;

    for (i = 0; numin != 0; ++i) {
	j = numin % baseout;
	if (j > 9)
	     numout[i] = j + 55; /* j -10 + 'A' */
	else
	     numout[i] = j + '0';
	numin /= baseout;
    }
    /* reverses numout[] */	/* k&r Exercise 1-19 */
    for (j = 0; j <= i/2-1; ++j) {
	 numout[i] = numout[j];
	 numout[j] = numout[i-1-j];
	 numout[i-1-j] = numout[i];
    }
    numout[i] = '\0';	/* k&r p30 */
}

void goback(int n) {
	if (n == 1)
		while (getchar() != '\n')
			;
	else {
		printf("\n 请按回车键继续...\n");
		while (getchar() != '\n')
			;
	}
}