📄 ilaplace.m
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function [A,b,x,t] = ilaplace(n,example) %ILAPLACE Test problem: inverse Laplace transformation. % % [A,b,x,t] = ilaplace(n,example) % % Discretization of the inverse Laplace transformation by means of % Gauss-Laguerre quadrature. The kernel K is given by % K(s,t) = exp(-s*t) , % and both integration intervals are [0,inf). % % The following examples are implemented, where f denotes % the solution, and g denotes the right-hand side: % 1: f(t) = exp(-t/2), g(s) = 1/(s + 0.5) % 2: f(t) = 1 - exp(-t/2), g(s) = 1/s - 1/(s + 0.5) % 3: f(t) = t^2*exp(-t/2), g(s) = 2/(s + 0.5)^3 % 4: f(t) = | 0 , t <= 2, g(s) = exp(-2*s)/s. % | 1 , t > 2 % % The quadrature points are returned in the vector t. % Reference: J. M. Varah, "Pitfalls in the numerical solution of linear % ill-posed problems", SIAM J. Sci. Stat. Comput. 4 (1983), 164-176. % Per Christian Hansen, IMM, Dec. 19, 2000. % Initialization. if (n <= 0), error('The order n must be positive'); end if (nargin == 1), example = 1; end % Compute equidistand collocation points s. s = (10/n)*[1:n]'; % Compute abscissas t and weights w from the eigensystem of the % symmetric tridiagonal system derived from the recurrence % relation for the Laguerre polynomials. Sorting of the % eigenvalues and -vectors is necessary. t = diag(2*[1:n]-1) - diag([1:n-1],1) - diag([1:n-1],-1); [Q,t] = eig(t); t = diag(t); [t,indx] = sort(t); w = Q(1,indx).^2; clear Q % Set up the coefficient matrix A. A = zeros(n,n); for i=1:n for j=1:n A(i,j) = (1-s(i))*t(j); end end A = exp(A)*diag(w); % Compute the right-hand side b and the solution x by means of % simple collocation. if (example==1) b = ones(n,1)./(s + .5); x = exp(-t/2); elseif (example==2) b = ones(n,1)./s - ones(n,1)./(s + .5); x = ones(n,1) - exp(-t/2); elseif (example==3) b = 2*ones(n,1)./((s + .5).^3); x = (t.^2).*exp(-t/2); elseif (example==4) b = exp(-2*s)./s; x = ones(n,1); f = find(t<=2); x(f) = zeros(length(f),1); else error('Illegal example') end
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