📄 form1.vb
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Imports System.Drawing.Drawing2D
Public Class Form1
Inherits System.Windows.Forms.Form
#Region " Windows 窗体设计器生成的代码 "
Public Sub New()
MyBase.New()
'该调用是 Windows 窗体设计器所必需的。
InitializeComponent()
'在 InitializeComponent() 调用之后添加任何初始化
End Sub
'窗体重写处置以清理组件列表。
Protected Overloads Overrides Sub Dispose(ByVal disposing As Boolean)
If disposing Then
If Not (components Is Nothing) Then
components.Dispose()
End If
End If
MyBase.Dispose(disposing)
End Sub
'Windows 窗体设计器所必需的
Private components As System.ComponentModel.IContainer
'注意:以下过程是 Windows 窗体设计器所必需的
'可以使用 Windows 窗体设计器修改此过程。
'不要使用代码编辑器修改它。
<System.Diagnostics.DebuggerStepThrough()> Private Sub InitializeComponent()
components = New System.ComponentModel.Container()
Me.Text = "Form1"
End Sub
#End Region
Protected Overrides Sub OnPaint(ByVal e As System.Windows.Forms.PaintEventArgs)
Dim g As Graphics = e.Graphics
'定义转换矩阵
Dim mat As New Matrix()
mat.Translate(0, 0)
'定义顶点,添加基数样条曲线到路径
Dim point1 As New Point(10, 100)
Dim point2 As New Point(80, 20)
Dim point3 As New Point(150, 300)
Dim point4 As New Point(200, 100)
Dim point5 As New Point(300, 200)
Dim point6 As New Point(500, 150)
Dim points As Point() = {point1, point2, point3, point4, point5, point6}
Dim gp As New GraphicsPath()
gp.AddCurve(points)
g.DrawPath(New Pen(Color.Black, 2), gp)
'展平曲线
gp.Flatten(mat, 5)
'获得路径上的关键点
Dim p() As PointF = gp.PathPoints
'给出要与曲线求交的直线段
Dim line1 As New CLine(New PointF(20, 400), New PointF(400, 50))
line1.Draw(g, Pens.Blue)
Dim interNum As Integer = -1
Dim intersec As Single()
Dim interPoints(5) As PointF
Dim i As Integer
'根据展平以后得到的多条直线段逐个与给定的直线段求交点
'最终得到的交点即可看作给定直线段与曲线的交点
For i = 0 To gp.PointCount - 2
Dim line2 As New CLine(p(i), p(i + 1))
intersec = LineLine(line1, line2)
If intersec(0) > 0 Then
interNum += 1
interPoints(interNum) = New PointF(intersec(1), intersec(2))
End If
Next
'用红色填充圆表示交点
For i = 0 To interNum
g.FillEllipse(Brushes.Red, interPoints(i).X - 3, interPoints(i).Y - 3, 6, 6)
Next
End Sub
End Class
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