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📄 math.asm

📁 这是一些例程
💻 ASM
字号:
        .MODEL  small, pascal, os_dos
        INCLUDE demo.inc
        .CODE

;* AddLong - Adds two double-word (long) integers.
;*
;* Shows:   Instructions - add     adc
;*          Operator - PTR
;*
;* Params:  Long1 - First integer
;*          Long2 - Second integer
;*
;* Return:  Sum as long integer

AddLong PROC,
        Long1:SDWORD, Long2:SDWORD

        mov     ax, WORD PTR Long1[0]   ; AX = low word, long1
        mov     dx, WORD PTR Long1[2]   ; DX = high word, long1
        add     ax, WORD PTR Long2[0]   ; Add low word, long2
        adc     dx, WORD PTR Long2[2]   ; Add high word, long2
        ret                             ; Result returned as DX:AX

AddLong ENDP

;* SubLong - Subtracts a double-word (long) integer from another.
;*
;* Shows:   Instructions -  sub     sbb
;*
;* Params:  Long1 - First integer
;*          Long2 - Second integer
;*
;* Return:  Difference as long integer

SubLong PROC,
        Long1:SDWORD, Long2:SDWORD

        mov     ax, WORD PTR Long1[0]   ; AX = low word, long1
        mov     dx, WORD PTR Long1[2]   ; DX = high word, long1
        sub     ax, WORD PTR Long2[0]   ; Subtract low word, long2
        sbb     dx, WORD PTR Long2[2]   ; Subtract high word, long2
        ret                             ; Result returned as DX:AX

SubLong ENDP


;* MulLong - Multiplies two unsigned double-word (long) integers. The
;* procedure allows for a product of twice the length of the multipliers,
;* thus preventing overflows. The result is copied into a 4-word data area
;* and a pointer to the data area is returned.
;*
;* Shows:   Instruction - mul
;*          Predefined equate - @data
;*
;* Params:  Long1 - First integer (multiplicand)
;*          Long2 - Second integer (multiplier)
;*
;* Return:  Pointer to quadword result

        .DATA
        PUBLIC result
result	QWORD	 ?	       ; Result from MulLong

        .CODE
MulLong PROC,
        Long1:DWORD, Long2:DWORD

        mov     ax, WORD PTR Long2[2]   ; Multiply long2 high word
        mul     WORD PTR Long1[2]       ;   by long1 high word
        mov     WORD PTR result[4], ax
        mov     WORD PTR result[6], dx

        mov     ax, WORD PTR Long2[2]   ; Multiply long2 high word
        mul     WORD PTR Long1[0]       ;   by long1 low word
        mov     WORD PTR result[2], ax
        add     WORD PTR result[4], dx
        adc     WORD PTR result[6], 0   ; Add any remnant carry

        mov     ax, WORD PTR Long2[0]   ; Multiply long2 low word
        mul     WORD PTR Long1[2]       ;   by long1 high word
        add     WORD PTR result[2], ax
        adc     WORD PTR result[4], dx
        adc     WORD PTR result[6], 0   ; Add any remnant carry

        mov     ax, WORD PTR Long2[0]   ; Multiply long2 low word
        mul     WORD PTR Long1[0]       ;   by long1 low word
        mov     WORD PTR result[0], ax
        add     WORD PTR result[2], dx
        adc     WORD PTR result[4], 0   ; Add any remnant carry

        mov     ax, OFFSET result       ; Return pointer
        mov     dx, @data               ;   to result
        ret

MulLong ENDP


;* ImulLong - Multiplies two signed double-word integers. Because the imul
;* instruction (illustrated here) treats each word as a signed number, its
;* use is impractical when multiplying multiword values. Thus the technique
;* used in the MulLong procedure can't be adopted here. Instead, ImulLong
;* is broken into three sections arranged in ascending order of computational
;* overhead. The procedure tests the values of the two integers and selects
;* the section that involves the minimum required effort to multiply them.
;*
;* Shows:   Instruction - imul
;*
;* Params:  Long1 - First integer (multiplicand)
;*          Long2 - Second integer (multiplier)
;*
;* Return:  Result as long integer

ImulLong PROC USES si,
        Long1:SDWORD, Long2:SDWORD

; Section 1 tests for integers in the range of 0 to 65,535. If both
; numbers are within these limits, they're treated as unsigned short
; integers.

        mov     ax, WORD PTR Long2[0]   ; AX = low word of long2
        mov     dx, WORD PTR Long2[2]   ; DX = high word of long2
        mov     bx, WORD PTR Long1[0]   ; BX = low word of long1
        mov     cx, WORD PTR Long1[2]   ; CX = high word of long1
        .IF     (dx == 0) && (cx == 0)  ; If both high words are zero,
        mul     bx                      ;   multiply the low words
        jmp     exit                    ;   and exit section 1
        .ENDIF

; Section 2 tests for integers in the range of -32,768 to 32,767. If
; both numbers are within these limits, they're treated as signed short
; integers.

        push    ax                      ; Save long2 low word
        push    bx                      ; Save long1 low word
        or      dx, dx                  ; High word of long2 = 0?
        jnz     notzhi2                 ; No?  Test for negative
        test    ah, 80h                 ; Low word of long2 in range?
        jz      notnlo2                 ; Yes?  long2 ok, so test long1
        jmp     sect3                   ; No?  Go to section 3
notzhi2:
        cmp     dx, 0FFFFh              ; Empty with sign flag set?
        jne     sect3                   ; No?  Go to section 3
        test    ah, 80h                 ; High bit set in low word?
        jz      sect3                   ; No?  Low word is too high
notnlo2:
        or      cx, cx                  ; High word of long1 = 0?
        jnz     notzhi1                 ; No?  Test for negative
        test    bh, 80h                 ; Low word of long1 in range?
        jz      notnlo1                 ; Yes?  long1 ok, so use sect 2
        jmp     sect3                   ; No?  Go to section 3
notzhi1:
        cmp     cx, 0FFFFh              ; Empty with sign flag set?
        jne     sect3                   ; No?  Go to section 3
        test    bh, 80h                 ; High bit set in low word?
        jz      sect3                   ; No?  Low word is too high
notnlo1:
        imul    bx                      ; Multiply low words
        pop     bx                      ; Clean stack
        pop     bx
        jmp     exit                    ; Exit section 2

; Section 3 involves the most computational overhead. It treats the two
; numbers as signed long (double-word) integers.

sect3:
        pop     bx                      ; Recover long1 low word
        pop     ax                      ; Recover long2 low word
        mov     si, dx                  ; SI = long2 high word
        push    ax                      ; Save long2 low word
        mul     cx                      ; long1 high word x long2 low word
        mov     cx, ax                  ; Accumulate products in CX
        mov     ax, bx                  ; AX = low word of long1
        mul     si                      ; Multiply by long2 high word
        add     cx, ax                  ; Add to previous product
        pop     ax                      ; Recover long2 low word
        mul     bx                      ; Multiply by long1 low word
        add     dx, cx                  ; Add to product high word
exit:
        ret                             ; Return result as DX:AX

ImulLong ENDP


;* DivLong - Divides an unsigned long integer by an unsigned short integer.
;* The procedure does not check for overflow or divide-by-zero.
;*
;* Shows:   Instruction -  div
;*
;* Params:  Long1 - First integer (dividend)
;*          Short2 - Second integer (divisor)
;*          Remn - Pointer to remainder
;*
;* Return:  Quotient as short integer

DivLong PROC USES di,
        Long1:DWORD, Short2:WORD, Remn:PWORD

        mov     ax, WORD PTR Long1[0]   ; AX = low word of dividend
        mov     dx, WORD PTR Long1[2]   ; DX = high word of dividend
        div     Short2                  ; Divide by short integer
        LoadPtr es, di, Remn            ; Point ES:DI to remainder
        mov     es:[di], dx             ; Copy remainder
        ret                             ; Return with AX = quotient

DivLong ENDP


;* IdivLong - Divides a signed long integer by a signed short integer.
;* The procedure does not check for overflow or divide-by-zero.
;*
;* Shows:   Instruction - idiv
;*
;* Params:  Long1 - First integer (dividend)
;*          Short2 - Second integer (divisor)
;*          Remn - Pointer to remainder
;*
;* Return:  Quotient as short integer

IdivLong PROC USES di,
        Long1:SDWORD, Short2:SWORD, Remn:PSWORD

        mov     ax, WORD PTR Long1[0]   ; AX = low word of dividend
        mov     dx, WORD PTR Long1[2]   ; DX = high word of dividend
        idiv    Short2                  ; Divide by short integer
        LoadPtr es, di, Remn            ; ES:DI = remainder
        mov     es:[di], dx             ; Copy remainder
        ret                             ; Return with AX = quotient

IdivLong ENDP


;* Quadratic - Solves for the roots of a quadratic equation of form
;*                        A*x*x + B*x + C = 0
;* using floating-point instructions. This procedure requires either a math
;* coprocessor or emulation code.
;*
;* Shows:   Instructions - sahf     fld1     fld     fadd     fmul
;*                         fxch     fsubr    fchs    fsubp    fstp
;*                         fst      fstsw    fdivr   fwait    ftst
;*
;* Params:  a - Constant for 2nd-order term
;*          b - Constant for 1st-order term
;*          c - Equation constant
;*          R1 - Pointer to 1st root
;*          R2 - Pointer to 2nd root
;*
;* Return:  Short integer with return code
;*          0 if both roots found
;*          1 if single root (placed in R1)
;*          2 if indeterminate

Quadratic PROC USES ds di si,
        aa:DWORD, bb:DWORD, cc:DWORD, r1:PDWORD, r2:PDWORD

        LOCAL status:WORD               ; Intermediate status

        LoadPtr es, di, r1              ; ES:DI points to 1st root
        LoadPtr ds, si, r2              ; DS:SI points to 2nd root
        sub     bx, bx                  ; Clear error code
        fld1                            ; Load top of stack with 1
        fadd    st, st                  ; Double it to make 2
        fld     st                      ; Copy to next register
        fmul    aa                      ; ST register = 2a
        ftst                            ; Test current ST value
        fstsw   status                  ; Copy status to local word
        fwait                           ; Ensure coprocessor is done
        mov     ax, status              ; Copy status into AX
        sahf                            ; Load flag register
        jnz     notzero                 ; If C3 set, then a = 0, in which case
                                        ;   solution is x = -c / b
        fld     cc                      ; Load c parameter
        fchs                            ; Reverse sign
        fld     bb                      ; Load b parameter
        ftst                            ; Test current ST value
        fstsw   status                  ; Copy status to local word
        fwait                           ; Ensure coprocessor is done
        mov     ax, status              ; Copy status into AX
        sahf                            ; Load flag register
        jz      exit2                   ; If C3 set, b = 0, in which case
                                        ;   division by zero
        fdiv                            ; Divide by b
        fstp    DWORD PTR es:[di]       ; Copy result and pop stack
        fstp    st                      ; Clean up stack
        jmp     exit1                   ; Return with code = 1
notzero:
        fmul    st(1), st               ; ST(1) register = 4a
        fxch                            ; Exchange ST and ST(1)
        fmul    cc                      ; ST register = 4ac
        ftst                            ; Test current ST value
        fstsw   status                  ; Copy status to local word
        fwait                           ; Ensure coprocessor is done
        mov     ax, status              ; Copy status into AX
        sahf                            ; Load flag register
        jp      exit2                   ; If C2 set, 4*a*c is infinite

        fld     bb                      ; Else load b parameter
        fmul    st, st                  ; Square it; ST register = b*b
        fsubr                           ; ST register = b*b - 4*a*c
        ftst                            ; Test current ST value
        fstsw   status                  ; Copy status to local word
        fwait                           ; Ensure coprocessor is done
        mov     ax, status              ; Copy status into AX
        sahf                            ; Load flag register
        jc      exit2                   ; If C0 set, b*b < 4ac
        jnz     tworoot                 ; If C3 set, b*b = 4ac, in which
        inc     bx                      ;   case only 1 root so set flag
tworoot:
        fsqrt                           ; Get square root
        fld     bb                      ; Load b parameter
        fchs                            ; Reverse sign
        fxch                            ; Exchange ST and ST1
        fld     st                      ; Copy square root to next reg
        fadd    st, st(2)               ; ST = -b + sqrt(b*b - 4*a*c)
        fxch                            ; Exchange ST and ST1
        fsubp   st(2), st               ; ST = -b - sqrt(b*b - 4*a*c)

        fdiv    st, st(2)               ; Divide 1st dividend by 2*a
        fstp    DWORD PTR es:[di]       ; Copy result, pop stack
        fdivr                           ; Divide 2nd dividend by 2*a
        fstp    DWORD PTR ds:[si]       ; Copy result, pop stack
        jmp     exit                    ; Return with code
exit2:
        inc     bx                      ; Error code = 2 for indeterminancy
        fstp    st                      ; Clean stack
exit1:
        inc     bx                      ; Error code = 1 for single root
        fstp    st                      ; Clean stack
exit:
        mov ax, bx
        ret

Quadratic ENDP

        END

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