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📁 网络工程师试题对你一定会用帮助
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      value=C>C.DECN<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1603 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.TECN<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>29 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; IEEE802.5令牌环(Tokenm 
      Ring)网中,时延是由__(1)__决定。&copy;) <BR>答: &nbsp;<INPUT class=radio name=text1643 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.站点时延和信号传话时延<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1643 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.令牌帧长短和数据帧长短<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1643 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.电缆长度和站点个数<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1643 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.数据传输单和信号传播速度<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>30 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 设有某一个令牌环网长度为 400 米,环上有 
      28 个站点,其数据传输率为 4MbpS,环上信号的传播速度为 200 米/μS,每个站点具有 1bit 时延,则环上可能存在的最大时延是&copy;) 
      <BR>答: &nbsp;<INPUT class=radio name=text1647 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.9<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1647 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.28<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1647 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.36<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1647 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.48<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>31 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 一个带宽为 3KHZ、信噪比为 30dB 
      的信道,能够达到的极限数据传输率为__(7)__。&copy;) <BR>答: &nbsp;<INPUT class=radio name=text1653 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.12Kbps<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1653 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.30Kbps<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1653 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.56Kbps<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1653 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.10Mbps<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>32 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 根据奈奎斯特第一定理,为了保证传输质量,为达到 
      3KbpS 的数据传输车需要的带宽为___(9)___。&copy;) <BR>答: &nbsp;<INPUT class=radio 
      name=text1657 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.3KHz<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1657 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.6KHz<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1657 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.2KHz<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1657 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.56KHz<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>33 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 
      与线路交换相比,分组交换最大的优点是__(11)__&copy;) <BR>答: &nbsp;<INPUT class=radio name=text1661 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.延迟时间小<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1661 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.可进行差错控制<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1661 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.缓冲区易于管理<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1661 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.便于标准化<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>34 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 与线路交换相比,设待传送数据总长度为 L 
      位分组长度为 P 位,其中头部开销长度为 H 位,源节点到目 的节点之间的链路数为 h,每个键路上的延迟时间为 D 秒,数据传输率为 B 
      bps,线路交换和虚电路建立连接的时间都为 S 秒,在分组交换方式下每个中间节点产生 d 
      位的延迟时间,则传送所有数据,数据报分组交换所需时间为__(15)__秒。&copy;) <BR>答: &nbsp;<INPUT class=radio 
      name=text1669 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=A>A. 
      (hd/B+P/B)*[L/(P-H)]<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1669 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.(hD+P/B)*[L/(P-H)] <BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1669 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.[(h-1)d/B+hD+P/B]*[L/(P-H)]<BR>&nbsp; &nbsp; &nbsp; <INPUT 
      class=radio name=text1669 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=D>D. 
      [(h-1)d/B+hD+P/B]*[L/P]<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>35 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 
      透明网桥的基本功能有学习、帧过滤和帧转发及生成树算法等功能,因此它可以决定网络中的路由,而网络中的各个站点均不负责路由选择。网桥从其某一端口收到正确的数据帧后,在其地址转发表中查找该帧要到达的目的站,若要到达的目的站仍然在该端口上,则会___(17)__。&copy;) 
      <BR>答: &nbsp;<INPUT class=radio name=text1673 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.向该端口转发此帧<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1673 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.丢弃此帧<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1673 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.将此帧作为地址探测帧<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1673 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=D>D. 
      利用此帧建立该端口的地址转换表<BR></TD></TR>
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    <TD align=middle height=212 width=29>36 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 图一为两个局域网 LAN1 和 LAN2 
      通过网桥 1 和网桥 2 互连后形成的网络结构。设站 A 
      发送一个帧,但其目的地址均不在这两个网桥的地址转发表中,为了有效地解决该类问题,可以在每个网桥中引入生成树算法,这样一来__(19)__。 &copy;) 
      <BR>
      <CENTER><IMG border=0 src="模拟考试15.files/200481394349wso3x8.gif"> 
      </CENTER><BR>答: &nbsp;<INPUT class=radio name=text1679 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.网络资源也会得到充分利用<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1679 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.网络的最佳路由也会得到确定<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1679 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.也限制了网络规模<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1679 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.也增加了网络延时<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>37 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 在使用路由器 R 的 TCP/IP 
      网络中,两主机通过一路由器互联,提供主机 A 和主机 B 应用层之间通信的层是__(21)__&copy;) <BR>答: &nbsp;<INPUT 
      class=radio name=text1684 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.应用层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1684 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.传输层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1684 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.IP层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1684 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.网络接口层<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>38 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 在使用路由器 R 的 TCP/IP 
      网络中,两主机通过一路由器互联,提供机器之间通信的层是__(22)__&copy;) <BR>答: &nbsp;<INPUT class=radio 
      name=text1688 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.应用层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1688 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.传输层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1688 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=C>C. 
      IP层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1688 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.网络接口层<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>39 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 对照 ISO/OSI 
      参考模型各个层中的网络安全服务,在物理层可以采用__(26)__加强通信线路的安全&copy;) <BR>答: &nbsp;<INPUT 
      class=radio name=text1690 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.防窃听技<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1690 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.防火墙技术<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1690 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.防病毒技术<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1690 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.防拒认技术 <BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>40 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; TCP 
      是一个面向连接的协议,采用__(32)___技术来实现可靠数据流的传送。&copy;) <BR>答: &nbsp;<INPUT class=radio 
      name=text1706 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.超时重传<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1706 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.肯定确认(捎带一个分组的序号)<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1706 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.超时重传和肯定确认(捎带一个分组的序号)<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1706 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.丢失重传和重复确认<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>41 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; SNMP 
      协议管理操作中管理代理主动向管理进程报告事件的操作是__(38)__。&copy;) <BR>答: &nbsp;<INPUT class=radio 
      name=text1715 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.get-request<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 

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