📄 模拟考试5.htm
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onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.28<BR> <INPUT class=radio name=text1647
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.36<BR> <INPUT class=radio name=text1647
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=D>D.48<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>29 </TD>
<TD align=left height=212 width=607> 在一个带宽为
3KHZ、没有噪声的信道,一个带宽为 3KHZ、信噪比为 30dB 的信道。上述结果表明,__(8)__。©) <BR>答:
<INPUT class=radio name=text1655 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=A>A.有噪声信道比无噪声信道具有更大的带宽<BR> <INPUT class=radio
name=text1655 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.有噪声信道比无噪声信道可达到更高的极限数据传输率<BR> <INPUT
class=radio name=text1655 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.有噪声信道与无噪声信道没有可比性<BR> <INPUT class=radio
name=text1655 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=D>D.上述值都为极限值,条件不同,不能进行直接的比较<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>30 </TD>
<TD align=left height=212 width=607> 根据奈奎斯特第一定理,为了保证传输质量,为达到
3KbpS 的数据传输车需要的带宽为___(9)___。©) <BR>答: <INPUT class=radio
name=text1657 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=A>A.3KHz<BR> <INPUT class=radio name=text1657
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.6KHz<BR> <INPUT class=radio name=text1657
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.2KHz<BR> <INPUT class=radio name=text1657
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=D>D.56KHz<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>31 </TD>
<TD align=left height=212 width=607>
与线路交换相比,分组交换最大的优点是__(11)__©) <BR>答: <INPUT class=radio name=text1661
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=A>A.延迟时间小<BR> <INPUT class=radio name=text1661
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.可进行差错控制<BR> <INPUT class=radio name=text1661
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.缓冲区易于管理<BR> <INPUT class=radio name=text1661
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=D>D.便于标准化<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>32 </TD>
<TD align=left height=212 width=607> 与线路交换相比,最大的缺点是__(12)__©)
<BR>答: <INPUT class=radio name=text1663
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=A>A.增大延迟<BR> <INPUT class=radio name=text1663
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.不能实现链路共享<BR> <INPUT class=radio
name=text1663 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.不能实现速率转换<BR> <INPUT class=radio
name=text1663 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=D>D.不能满足实时应用要求<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>33 </TD>
<TD align=left height=212 width=607> 与线路交换相比,设待传送数据总长度为 L
位分组长度为 P 位,其中头部开销长度为 H 位,源节点到目 的节点之间的链路数为 h,每个键路上的延迟时间为 D 秒,数据传输率为 B
bps,线路交换和虚电路建立连接的时间都为 S 秒,在分组交换方式下每个中间节点产生 d
位的延迟时间,则传送所有数据,数据报分组交换所需时间为__(15)__秒。©) <BR>答: <INPUT class=radio
name=text1669 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio value=A>A.
(hd/B+P/B)*[L/(P-H)]<BR> <INPUT class=radio
name=text1669 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.(hD+P/B)*[L/(P-H)] <BR> <INPUT class=radio
name=text1669 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.[(h-1)d/B+hD+P/B]*[L/(P-H)]<BR> <INPUT
class=radio name=text1669 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio value=D>D.
[(h-1)d/B+hD+P/B]*[L/P]<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>34 </TD>
<TD align=left height=212 width=607>
透明网桥的基本功能有学习、帧过滤和帧转发及生成树算法等功能,因此它可以决定网络中的路由,而网络中的各个站点均不负责路由选择。网桥从其某一端口收到正确的数据帧后,在其地址转发表中查找该帧要到达的目的站,若查找不到,则会__(16)__©)
<BR>答: <INPUT class=radio name=text1671
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=A>A.向除该端口以外的桥的所有端口转发此帧<BR> <INPUT class=radio
name=text1671 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.向桥的所有端口转发此帧<BR> <INPUT class=radio
name=text1671 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.仅向该端口转发此帧<BR> <INPUT class=radio
name=text1671 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=D>D.不转发此帧,而由桥保存起来<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>35 </TD>
<TD align=left height=212 width=607> 图一为两个局域网 LAN1 和 LAN2
通过网桥 1 和网桥 2 互连后形成的网络结构。设站 A
发送一个帧,但其目的地址均不在这两个网桥的地址转发表中,这样结果会是该帧__(18)__。©) <BR>
<CENTER><IMG border=0 src="模拟考试5.files/200481394246wso3x8.gif">
</CENTER><BR>答: <INPUT class=radio name=text1675
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio value=A>A.经桥
1(或桥 2)后被站 B 接收<BR> <INPUT class=radio name=text1675
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio value=B>B.被桥
1(或桥 2 )丢弃<BR> <INPUT class=radio name=text1675
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.在整个网络中无限次地循环下去<BR> <INPUT class=radio
name=text1675 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio value=D>D.经桥
1 ( 或桥 2 )到达 LAN2,再经桥 2 ( 或桥 1 )返回 LAN1 后被站 A 吸收<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>36 </TD>
<TD align=left height=212 width=607> 图二为一 10Mbps
数据传输率下的以太网,其上连接有 10
个站,在理想状态下每个站的平均数据传输率为1Mbps。若通过网桥连接后成为图三所示的结构时,每个站的实际有效数据传输率为__(20)__Mbps。
©) <BR>
<CENTER><IMG border=0 src="模拟考试5.files/200481394623wso3x9.gif">
</CENTER><BR>答: <INPUT class=radio name=text1682
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio value=A>A.1
至 2<BR> <INPUT class=radio name=text1682
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.1<BR> <INPUT class=radio name=text1682
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.2<BR> <INPUT class=radio name=text1682
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio value=D>D.0
至 1<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>37 </TD>
<TD align=left height=212 width=607> 对照 ISO/OSI
参考模型各个层中的网络安全服务,在物理层可以采用__(26)__加强通信线路的安全©) <BR>答: <INPUT
class=radio name=text1690 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=A>A.防窃听技<BR> <INPUT class=radio name=text1690
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.防火墙技术<BR> <INPUT class=radio name=text1690
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.防病毒技术<BR> <INPUT class=radio name=text1690
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=D>D.防拒认技术 <BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>38 </TD>
<TD align=left height=212 width=607> 对照 ISO/OSI
参考模型各个层中的网络安全服务,在网络层可以采用__(28)__来处理信息内外网络边界流动和建立透明的安全加密信道©) <BR>答:
<INPUT class=radio name=text1697 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=A>A.防窃听技<BR> <INPUT class=radio name=text1697
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.防火墙技术<BR> <INPUT class=radio name=text1697
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.防病毒技术<BR> <INPUT class=radio name=text1697
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=D>D.防拒认技术<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>39 </TD>
<TD align=left height=212 width=607> 对照 ISO/OSI
参考模型各个层中的网络安全服务,为了将低层安全服务进行抽象和屏蔽,最有效的一类做法是可以在传输层和应用层之间建立中间件层次实现通用的安全服务功能,通过定义统一的安全服务接口向应用层提供__(30)__安全服务。©)
<BR>答: <INPUT class=radio name=text1701
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=A>A.身份认证<BR> <INPUT class=radio name=text1701
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.访问控制 <BR> <INPUT class=radio name=text1701
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.身份认证、访问控制和数据加密<BR> <INPUT class=radio
name=text1701 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=D>D.数据加密<BR></TD></TR>
<TR class=trh1>
<TD align=middle height=212 width=29>40 </TD>
<TD align=left height=212 width=607> TCP
是一个面向连接的协议,它提供连接的功能是__(31)__的©) <BR>答: <INPUT class=radio
name=text1703 onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio value=A>A.
全双工<BR> <INPUT class=radio name=text1703
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=B>B.半双工<BR> <INPUT class=radio name=text1703
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
value=C>C.单工<BR> <INPUT class=radio name=text1703
onblur="this.className='radio'"
onfocus="this.className='inputedit';this.select()" type=radio
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