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📁 网络工程师试题对你一定会用帮助
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      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.HDLC<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1601 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.LAP-D<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1601 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.LAP-F<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>28 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; IEEE802.5令牌环(Tokenm 
      Ring)网中,要保证环网的正常运行,环的时延必须有一个最低限度,即__(2)__。&copy;) <BR>答: &nbsp;<INPUT 
      class=radio name=text1644 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.数据帧长<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1644 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.令牌帧长<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1644 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.信号传播时延<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1644 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.站点个数<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>29 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 在一个带宽为 
      3KHZ、没有噪声的信道,传输二进制信号时能够达到的极限数据传输率为__(6)__。&copy;) <BR>答: &nbsp;<INPUT 
      class=radio name=text1651 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.3Kbps<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1651 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.6Kbps<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1651 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.56Kbps<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1651 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.10Mbps<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>30 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 根据奈奎斯特第一定理,为了保证传输质量,为达到 
      3KbpS 的数据传输车需要的带宽为___(9)___。&copy;) <BR>答: &nbsp;<INPUT class=radio 
      name=text1657 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.3KHz<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1657 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.6KHz<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1657 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.2KHz<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1657 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.56KHz<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>31 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 
      在一个无限带宽的无噪声信道上,传输二进制信号,当信号的带宽为 3KHz 时,能达到的极限数据传输率为__(10)__Kbps 。&copy;) <BR>答: 
      &nbsp;<INPUT class=radio name=text1659 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.1.5<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1659 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.3<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1659 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.6<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1659 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=D>D.3 
      log23<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>32 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 
      透明网桥的基本功能有学习、帧过滤和帧转发及生成树算法等功能,因此它可以决定网络中的路由,而网络中的各个站点均不负责路由选择。网桥从其某一端口收到正确的数据帧后,在其地址转发表中查找该帧要到达的目的站,若查找不到,则会__(16)__&copy;) 
      <BR>答: &nbsp;<INPUT class=radio name=text1671 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.向除该端口以外的桥的所有端口转发此帧<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1671 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.向桥的所有端口转发此帧<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1671 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.仅向该端口转发此帧<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1671 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.不转发此帧,而由桥保存起来<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>33 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 
      透明网桥的基本功能有学习、帧过滤和帧转发及生成树算法等功能,因此它可以决定网络中的路由,而网络中的各个站点均不负责路由选择。网桥从其某一端口收到正确的数据帧后,在其地址转发表中查找该帧要到达的目的站,若要到达的目的站仍然在该端口上,则会___(17)__。&copy;) 
      <BR>答: &nbsp;<INPUT class=radio name=text1673 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.向该端口转发此帧<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1673 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.丢弃此帧<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1673 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.将此帧作为地址探测帧<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1673 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=D>D. 
      利用此帧建立该端口的地址转换表<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>34 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 图一为两个局域网 LAN1 和 LAN2 
      通过网桥 1 和网桥 2 互连后形成的网络结构。设站 A 
      发送一个帧,但其目的地址均不在这两个网桥的地址转发表中,这样结果会是该帧__(18)__。&copy;) <BR>
      <CENTER><IMG border=0 src="模拟考试7.files/200481394246wso3x8.gif"> 
      </CENTER><BR>答: &nbsp;<INPUT class=radio name=text1675 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=A>A.经桥 
      1(或桥 2)后被站 B 接收<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1675 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=B>B.被桥 
      1(或桥 2 )丢弃<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1675 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.在整个网络中无限次地循环下去<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1675 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=D>D.经桥 
      1 ( 或桥 2 )到达 LAN2,再经桥 2 ( 或桥 1 )返回 LAN1 后被站 A 吸收<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>35 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 在使用路由器 R 的 TCP/IP 
      网络中,两主机通过一路由器互联,提供主机 A 和主机 B 应用层之间通信的层是__(21)__&copy;) <BR>答: &nbsp;<INPUT 
      class=radio name=text1684 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.应用层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1684 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.传输层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1684 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.IP层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1684 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.网络接口层<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>36 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 在使用路由器 R 的 TCP/IP 
      网络中,两主机通过一路由器互联,提供机器之间通信的层是__(22)__&copy;) <BR>答: &nbsp;<INPUT class=radio 
      name=text1688 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.应用层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1688 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.传输层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1688 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=C>C. 
      IP层<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1688 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.网络接口层<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>37 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 对照 ISO/OSI 
      参考模型各个层中的网络安全服务,在物理层可以采用__(26)__加强通信线路的安全&copy;) <BR>答: &nbsp;<INPUT 
      class=radio name=text1690 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.防窃听技<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1690 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.防火墙技术<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1690 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.防病毒技术<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1690 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.防拒认技术 <BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>38 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 对照 ISO/OSI 
      参考模型各个层中的网络安全服务,在数据链路层,可以采用__(27)__进行链路加密&copy;) <BR>答: &nbsp;<INPUT 
      class=radio name=text1694 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.公钥基础<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1694 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.Kerberos 鉴别<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio 
      name=text1694 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.通信保密机 <BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1694 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio value=D>D.CA 
      认证中心<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>39 </TD>
    <TD align=left height=212 width=607>&nbsp; &nbsp; 对照 ISO/OSI 
      参考模型各个层中的网络安全服务,在网络层可以采用__(28)__来处理信息内外网络边界流动和建立透明的安全加密信道&copy;) <BR>答: 
      &nbsp;<INPUT class=radio name=text1697 onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=A>A.防窃听技<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1697 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=B>B.防火墙技术<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1697 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=C>C.防病毒技术<BR>&nbsp; &nbsp; &nbsp; <INPUT class=radio name=text1697 
      onblur="this.className='radio'" 
      onfocus="this.className='inputedit';this.select()" type=radio 
      value=D>D.防拒认技术<BR></TD></TR>
  <TR class=trh1>
    <TD align=middle height=212 width=29>40 </TD>

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