1489.cpp
来自「2^x mod n = 1 acm竞赛题 Give a number n, fi」· C++ 代码 · 共 26 行
CPP
26 行
#include<iostream>
using namespace std;
int main()
{
int n,t,i,able;
while(cin>>n)
{
i=1;
if(n%2==0||n<2)cout<<"2^? mod "<<n<<" = 1"<<endl;
else
{
able=1;
t=2;
while(1)
{
while(t>n)t-=n;
if(t%n==1){cout<<"2^"<<able<<" mod "<<n<<" = 1"<<endl;break;}
++able;
t=t*2;
}
}
}
}
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?