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📄 inline.dcf

📁 用Java实现的编译器。把源代码编译成SPARC汇编程序
💻 DCF
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// Inline testsclass Program {  int g1;  // should inline if doing simple procedures  int plus (int a, int b) {    return (a + b);  }  // may inline if doing simple procedures  int twice(int a) {    return (plus(a, a));  }  // probably shouldn't inline unless inlining everything  int long(int a) {  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  a = a + g1; a = a + g1; a = a + g1; a = a + g1; a = a + g1;  return (a);  }  // this is recursive, so it can't be completely inlined  int rec(int q) {    if (q == 0) {      return (0);    }    return ( 1 + rec ( q - 1));  }  // tail recursive. could be inlined, but pretty tricky  int tailrec(int q, int sf) {    if (q == 0) {      return (sf);    }    return (tailrec(q - 1, sf + 1)); // good compilers make this a goto.  }  // if tailrec is inlined, this should be too.  int rec2(int q) {    return (tailrec(q, 0));  }    void main() {    int c;    callout("printf","G1? ");    g1 = callout("readint");    c = long(1) + long(2) + long(3);  // should probably not inline    // but points won't be lost for doing so    callout("printf","%d\n", twice(4)); // should probably inline    callout("printf","%d\n", c);    callout("printf","%d\n", rec(6));     callout("printf","%d\n", rec2(4));     c = 0;    while (c < 5) {      callout("printf","%d\n", plus(c,c)); // should definitely inline      c = c + 1;    }  }}          

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