h_20_3_4.m

来自「关于LDPC编码的MATLAB实现仿镇,求关于LDPC码的FPGA实现」· M 代码 · 共 36 行

%(20,3,4) check metrix, whose gap is 3 and girth is more than 4.
H =[ 1     1     1     0     0     0     0     0     1     0     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     1     1     1     0     0     1     0     0     0     0     0     0     0     0     0     0
     1     0     0     1     1     0     0     0     0     0     1     0     0     0     0     0     0     0     0     0
     0     1     0     0     0     0     0     1     0     0     1     1     0     0     0     0     0     0     0     0
     0     0     1     0     0     0     1     1     0     0     0     0     1     0     0     0     0     0     0     0
     1     0     0     0     0     0     0     0     0     0     0     1     1     1     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     1     1     0     1     0     0     1     0     0     0     0     0
     0     0     1     1     0     0     0     0     0     1     0     0     0     0     0     1     0     0     0     0
     0     0     0     0     0     0     1     0     0     0     0     0     0     1     0     1     1     0     0     0
     0     0     0     0     0     0     0     0     0     0     1     0     0     1     1     0     0     1     0     0
     0     0     0     0     0     1     0     1     0     0     0     0     0     0     0     0     0     1     1     0
     0     0     0     0     0     1     0     0     0     0     0     0     0     0     1     0     1     0     0     1
     0     1     0     1     0     0     0     0     0     0     0     0     0     0     0     0     0     0     1     1
     0     0     0     0     0     0     0     0     0     0     0     0     1     0     0     1     0     1     0     1
     0     0     0     0     1     0     0     0     1     0     0     0     0     0     0     0     1     0     1     0];
 %对上面的H进行了列置换，从而保证编码的顺利进行
 H =[1     0     1     0     0     0     0     1     1     0     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     1     1     1     0     0     1     0     0     0     0     0     0     0     0     0     0
     1     0     0     1     1     0     0     0     0     0     1     0     0     0     0     0     0     0     0     0
     0     1     0     0     0     0     0     1     0     0     1     1     0     0     0     0     0     0     0     0
     0     1     1     0     0     0     1     0     0     0     0     0     1     0     0     0     0     0     0     0
     1     0     0     0     0     0     0     0     0     0     0     1     1     1     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     1     1     0     1     0     0     1     0     0     0     0     0
     0     0     1     1     0     0     0     0     0     1     0     0     0     0     0     1     0     0     0     0
     0     0     0     0     0     0     1     0     0     0     0     0     0     1     0     1     1     0     0     0
     0     0     0     0     0     0     0     0     0     0     1     0     0     1     1     0     0     1     0     0
     0     1     0     0     0     1     0     0     0     0     0     0     0     0     0     0     0     1     1     0
     0     0     0     0     0     1     0     0     0     0     0     0     0     0     1     0     1     0     0     1
     0     0     0     1     0     0     0     1     0     0     0     0     0     0     0     0     0     0     1     1
     0     0     0     0     0     0     0     0     0     0     0     0     1     0     0     1     0     1     0     1
     0     0     0     0     1     0     0     0     1     0     0     0     0     0     0     0     1     0     1     0];
 
 C =[
     
     1     0     0     0     0     0     1     0    11     0     6     0    11     0     1     0     0     0     0     0     1