📄 proaddpicsave.asp
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<!-- #include file = "include/sysbase.asp" -->
<!--#INCLUDE FILE = "include/upload_5xsoft.inc"-->
<%
dim uploadObj, szPath, fileObj, szFileName, tmp
dim strSQL
dim nID, szType
set uploadObj = new upload_5xSoft
set fileObj = uploadObj.File("filePic") '与上传表单中的file1相对应
nID = uploadObj.Form("id")
szType = uploadObj.Form("type")
'判断参数是否正确
if nID = "" or szType = "" then
Response.Write "有错误发生,无法获取上传参数<br>"
Response.Write "<a href=""javascript:window.close();"">[关闭]</a>"
Response.End()
end if
szPath = "../"& szType &"/"
if fileObj.FileSize>0 then '如果 FileSize > 0 说明有文件数据
tmp = fileObj.FileName
'以nID+原文件扩展名重新命名上传文件
szFileName = nID & right(tmp, (len(tmp)-InStrRev(tmp,".")+1))
Response.Write szFileName
fileObj.SaveAs Server.MapPath(szPath & szFileName) '保存文件
end if
strSQL = "UPDATE product SET "& szType &" = '"& szFileName &"' WHERE id = "& nID
conn.Execute(strSQL)
'释放对象,关闭连接
set fileObj = nothing
CloseConn()
%>
<script language = Javascript>
<!--
alert("上传图片成功!");
opener.location.reload();
window.close();
-->
</script>
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