📄 求解最短路的floyd算法程序.htm
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<B>floyd算法</B><BR>最近两天做了一个图论的题目，其中有一个求最短路的，我用的是floyd算法，现贴出来，供大家参考。<BR>-------------------------------------------------------------------<BR>function
[LeR,r]=floyd(w)<BR>%[LeR,r]=floyd(w)<BR>%w;邻接矩阵<BR>%LeR:为所得的最短路矩阵<BR>%参考文献：谢政，李建平：网络算法与复杂性理论.国防科技出版社.1995,第一版。<BR>n=size(w,1);<BR>u.m_1=w;<BR>r.m_1=ones(n,1)*[1:n];<BR><BR>m=1;<BR>while
m~=n+1 <BR> for
i=1:n<BR> for
j=1:n<BR>
if
u.m_1(i,j)<=u.m_1(i,m)+u.m_1(m,j)<BR>
r.m(i,j)=r.m_1(i,j);<BR>
else<BR>
r.m(i,j)=r.m_1(i,m);<BR>
end<BR>
u.m(i,j)=min(u.m_1(i,j),u.m_1(i,m)+u.m_1(m,j));<BR> end<BR>
end<BR> u.m_1=u.m;<BR> r.m_1=r.m;<BR> m=m+1;<BR>end<BR><BR>LeR=u.m;<BR>--------------------------------------------------------------------------<BR>最短轨：<BR>function
[Road]=FindRoad(var1,var2,r)<BR>%Road=cell(size(r.m));<BR>Rola=0;<BR>Road=var1;<BR>while
Rola~=var2<BR> Rola=r.m(var1,var2);<BR> Road=[Road
Rola];<BR> var1=Rola;<BR>end<IMG
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