📄 mubiaof.m
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function Z=mubiaof(x,mu,sigma)
C=[1.7 2.25 4.5 1.12];%托运单价
v=[0.0012 0.0015 0.003 0.0008];%单位质量的体积
for i=1:4
a=normcdf(x(i+4),mu(i),sigma(i))-normcdf(0,mu(i),sigma(i));
a=1./(sqrt(2.*pi).*sigma(i)).*a.*C(i).*x(i);
% b0=1./(sqrt(2.*pi).*sigma(i));
% b1=sigma(i).^2;
% b2=exp(-mu(i).^2./(2.*b1));
% b3=exp(-(x(i+4)-mu(i)).^2./(2.*b1));
% b4=normcdf((x(i+4)-mu(i))./sigma(i),0,1)-normcdf(-mu(i)./sigma(i),0,1);
% a=b0.*b1.*(b2-b3)+sigma(i).*mu(i).*b4;
tmp(i)=(1./(sqrt(2.*pi).*sigma(i))).*(normcdf(24000,mu(i),sigma(i))-normcdf(x(i+4),mu(i),sigma(i))).*C(i).*x(i+4)+a;
end
% s=x(9:12);
% m=[x(13:16);x(17:20);x(21:24)];
% if m*v'<=9.084
% if sum(m)<= s
% if sum(m')<=8000
Z=sum(tmp);%满足约束条件才可输出
% return;
% end
% end
% end
% end
% Z=0;%不满足约束条件则置零
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