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📄 planecrash.java

📁 利用java实现一个非线程规划问题
💻 JAVA
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public class planecrash
{ public static void main(String[] args)
  { boolean [][] number=new boolean[6][6];
    double x[]={0,150,85,150,145,130};
    double y[]={0,140,85,155,50,150};
    double h[]={Math.PI*52/180,Math.PI*243/180,Math.PI*236/180,Math.PI*220.5/180,Math.PI*159/180,Math.PI*230/180};
    double v=800;
    double [] t=new double[6];
    double [][] T=new double[6][6];
    double a,b,c;
    double [][] d=new double[6][6];
    for (int i=0;i<=5;i++)
    {if ((h[i]>=0)&(h[i]<=Math.PI/2))
       t[i]=Math.min((double)((160-x[i])/(v*Math.cos(h[i]))),(double)((160-y[i])/(v*Math.sin(h[i]))));
     if((h[i]>Math.PI/2)&(h[i]<=Math.PI))
       t[i]=Math.min((double)((-1)*x[i]/(v*Math.cos(h[i]))),(double)((160-y[i])/(v*Math.sin(h[i]))));
     if((h[i]>Math.PI)&(h[i]<=Math.PI*3/2))
         t[i]=Math.min((double)((-1)*x[i]/(v*Math.cos(h[i]))),(double)((-1)*y[i]/(v*Math.sin(h[i]))));
     if((h[i]>Math.PI*3/2)&(h[i]<=Math.PI*2))
                t[i]=Math.min((double)((160-x[i])/(v*Math.cos(h[i]))),(double)((-1)*y[i]/(v*Math.sin(h[i]))));
    }
    for (int i=0;i<=4;i++)
      for (int j=i+1;j<=5;j++)
       T[i][j]=Math.min(t[i],t[j]);
    for(int i=0;i<=4;i++)
      for(int j=i+1;j<=5;j++)
       {a=Math.pow(v,2)*(Math.pow(Math.cos(h[i])-Math.cos(h[j]),2)+Math.pow(Math.sin(h[i])-Math.sin(h[j]),2));
        b=v*((x[i]-x[j])*(Math.cos(h[i])-Math.cos(h[j]))+(y[i]-y[j])*(Math.sin(h[i])-Math.sin(h[j])));
        c=Math.pow(x[i]-x[j],2)+Math.pow(y[i]-y[j],2);
        if(b>=0)
          d[i][j]=c;
        
        if(b<0&b>(-1)*a*T[i][j])
            d[i][j]=c-Math.pow(b,2)/a;
        if (b<=(-1)*a*T[i][j])
            d[i][j]=a*Math.pow(T[i][j],2)+2*b*T[i][j]+c;}
     for(int i=0;i<=4;i++)
       for(int j=i+1;j<=5;j++)
        if (d[i][j]<=64)
         { number[i][j]=true;
           System.out.println("plane"+i+" "+"plane"+j+" "+"will crash");}
        else
          number[i][j]=false;   
    }
}

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