lms test.m

自己编的基于最抖下降法

data=2*binornd(1,0.5*ones(1,50))-1;
l=1;
for n=1:3
    h(n)=0.5*(1+cos(2*pi*(n-2)/rou(dif)));
end
x=conv(data,h);
xi=x((length(h)+1):length(x)); %x[4]~x[502]
xn=xi+sqrt(var_v)*randn(length(xi),1)';
d=data((tao+1):data_len);
for n=1:(length(xn)-p)
    x1=xn(n:n+p-1)';
    y1(n)=w'*x1;
    e(n)=d(n)-y(n);
    w=w+mu*e(n)*x1;
end