一个8×8点阵字符显示.c

来自「基于Proteus的51系列单片机设计与仿真」· C语言 代码 · 共 41 行

/*************************************************************************************
                                一个8×8点阵字符显示
						 8x8点阵循环显示I L O V E Y O U 
****************************************************************************************/
#include"reg51.h"
#define uint unsigned int
#define uchar unsigned char
const uchar tab1[]={
 0x00,0x00,0x42,0x7E,0x42,0x42,0x00,0x00,		//;"I"
 0x00,0x42,0x7E,0x42,0x02,0x02,0x02,0x00,		//;"L"
 0x00,0x3C,0x22,0x42,0x42,0x22,0x3C,0x00,		//;"O"
 0x00,0x40,0x70,0x0C,0x0C,0x70,0x40,0x00,		//;"V"
 0x00,0x42,0x7E,0x4A,0x4A,0x5A,0x22,0x00,		//;"E"
 0x00,0x40,0x62,0x1E,0x12,0x60,0x40,0x00,		//;"Y"
 0x00,0x3C,0x22,0x42,0x42,0x22,0x3C,0x00,		//;"O"
 0x00,0x7C,0x46,0x02,0x02,0x7C,0x40,0x00		//;"U"
 };
const uchar tab2[]={0x00,0x01,0x02,0x03,0x04,0x05,0x06,0x07};// 扫描代码
void delay(uint n)     
{   uint i;
         for(i=0;i<n;i++);
}
void main(void)
{     
	char j,r,q=0,t=0;
	while(1)
	{
		for(r=0;r<15;r++)
	   		for(j=q;j<8+q;j++)
	    		{  
		   			P3=tab2[t++];
           			P0=tab1[j];
           			delay(555);
           			if(t==8)
       	    		t=0;
				}
		q=q+8;
		if(q==64)
		q=0;
    }    
}