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width="85%" class="body18black">C++习题与解析(引用-04)</TD>
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<TD class="body12black" >题6.阅读下面的程序与输出结果，添加一个拷贝构造函数来完善整个程序<BR>
#include<iostream.h><BR>class
Cat<BR>{<BR>
public:<BR>
Cat();<BR>
Cat(const Cat
&);<BR>
~Cat();<BR>
int getage()const{return
*itsage;}<BR>
void setage(int
age){*itsage=age;}<BR>
protected:<BR>
int
*itsage;<BR>};<BR>Cat::Cat()<BR>{<BR>
itsage=new int;<BR>
*itsage=5;<BR>}<BR>Cat::~Cat()<BR>{<BR>
delete itsage;<BR>
itsage=0;<BR>}<BR>void
main()<BR>{<BR> Cat
frisky;<BR>
cout<<"frisky's
age:"<<frisky.getage()<<endl;<BR>
cout<<"setting frisky to
6...\n";<BR>
frisky.setage(6);<BR>
cout<<"creating boots from
frisky\n";<BR> Cat
boots(frisky);<BR>
cout<<"frisky's
age:"<<frisky.getage()<<endl;<BR>
cout<<"boots'age:"<<boots.getage()<<endl;<BR>
cout<<"setting frisky to
7...\n";<BR>
frisky.setage(7);<BR>
cout<<"frisky's
age:"<<frisky.getage()<<endl;<BR>
cout<<"boots'age:"<<boots.getage()<<endl;<BR>}<BR><BR>当添加了拷贝构造函数后，程序的运行结果为：<BR>frisky's
age:5<BR>setting frisky to 6...<BR>creating boots
from frisky<BR>frisky's
age:6<BR>boots'age:6<BR>setting frisky to
7...<BR>frisky's
age:7<BR>boots'age:6<BR><BR>解：<BR>
添加的拷贝构造函数如下：<BR>Cat::Cat(const Cat&
c)<BR>{<BR> itsage=new
int;<BR>
*itsage=*c.itsage;<BR>}<BR><BR>-----------------------------------------------<BR><BR><FONT
color=#0000ff>题7.设计一个类Sample,有一个私有数据成员，建立该类的四个对象s1(n=10)、s2(n=20)、s3(n=30)、和s4(n=40)，建立一个成员函数实现这些对象n值的累加。<BR></FONT>解：<BR>
依题意，建立一个成员函数add()，其参数为Sample对象引用，用于累加对象n值。<BR>程序如下：<BR>#include<iostream.h><BR>class
Sample<BR>{<BR> int
n;<BR>
public:<BR>
Sample(){}<BR>
Sample (int
i){n=i;}<BR>
void add(Sample
&s) //
对象引用作为参数<BR>
{<BR>
if(&s==this) //
不能自己相加，this是当前对象的指针<BR>
cout<<"自己不能相加"<<endl;<BR>
else
n+=s.n;<BR>
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