📄 frmbitonoff.frm
字号:
VERSION 5.00
Begin VB.Form FrmBitOnOff
BorderStyle = 1 'Fixed Single
Caption = "位强制开/关"
ClientHeight = 2355
ClientLeft = 45
ClientTop = 330
ClientWidth = 3795
LinkTopic = "Form1"
MaxButton = 0 'False
MinButton = 0 'False
ScaleHeight = 2355
ScaleWidth = 3795
StartUpPosition = 3 'Windows Default
Begin VB.CommandButton Command1
Caption = "返回"
Height = 495
Left = 1440
TabIndex = 6
Top = 1440
Width = 975
End
Begin VB.CommandButton CmdBitOff
Height = 495
Left = 2640
Picture = "FrmBitOnOff.frx":0000
Style = 1 'Graphical
TabIndex = 3
Top = 1440
Width = 1095
End
Begin VB.CommandButton CmdBitOn
Height = 495
Left = 120
MouseIcon = "FrmBitOnOff.frx":0442
Picture = "FrmBitOnOff.frx":0884
Style = 1 'Graphical
TabIndex = 2
Top = 1440
Width = 1095
End
Begin VB.TextBox TxtBitAddress
Height = 375
Left = 1440
TabIndex = 1
Top = 480
Width = 1095
End
Begin VB.Label Label3
Caption = "关断"
Height = 255
Left = 2760
TabIndex = 5
Top = 1080
Width = 495
End
Begin VB.Label Label2
Caption = "开通"
Height = 255
Left = 480
TabIndex = 4
Top = 1080
Width = 495
End
Begin VB.Label Label1
Caption = "位地址:"
Height = 255
Left = 1680
TabIndex = 0
Top = 120
Width = 735
End
End
Attribute VB_Name = "FrmBitOnOff"
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = False
Attribute VB_PredeclaredId = True
Attribute VB_Exposed = False
Private Sub CmdBitOff_Click()
Dim Sum As Integer
Dim instring As String
Dim sumstring As String
Dim sumstring2 As String
Dim time1
'判断有无起始地址
If TxtBitAddress.Text = "" Then
response = MsgBox("无起始地址!", 48, title)
TxtBitAddress.SetFocus
GoTo end1:
Else
End If
'将地址调整为4位
If Len(TxtBitAddress.Text) <> 4 Then
Select Case Len(TxtBitAddress.Text)
Case 1
TxtBitAddress.Text = "0" + "0" + "0" + TxtBitAddress.Text
Case 2
TxtBitAddress.Text = "0" + "0" + TxtBitAddress.Text
Case 3
TxtBitAddress.Text = "0" + TxtBitAddress.Text
End Select
End If
'地址和校验
Sum = &H38
For i = 1 To 4
Sum = Sum + Asc(Mid(TxtBitAddress.Text, i, 1))
Next i
Sum = Sum + 3
sumstring = Hex(Sum)
sumstring2 = Right(sumstring, 2)
FrmMain.MSComm1.PortOpen = True
FrmMain.MSComm1.Output = Chr(&H2) + Chr(&H38) 'STX CMD 8
FrmMain.MSComm1.Output = TxtBitAddress.Text
FrmMain.MSComm1.Output = Chr(3) 'ETX
FrmMain.MSComm1.Output = sumstring2 'SUM
'接收应答:
time1 = Timer
Do
DoEvents
Loop Until FrmMain.MSComm1.InBufferCount >= 1 Or (Timer - time1) > 10
instring = FrmMain.MSComm1.Input
If (Timer - time1) > 10 Then
MsgBox "PLC没有响应!"
Else
If instring = Chr(6) Then
MsgBox "数据传输成功!"
Else
If instring = Chr(&H15) Then
MsgBox "数据传输失败!请重试"
Else
End If
End If
End If
FrmMain.MSComm1.PortOpen = False
end1:
End Sub
Private Sub CmdBitOn_Click()
Dim Sum As Integer
Dim instring As String
Dim sumstring As String
Dim sumstring2 As String
Dim time1
'判断有无起始地址
If TxtBitAddress.Text = "" Then
response = MsgBox("无起始地址!", 48, title)
TxtBitAddress.SetFocus
GoTo end1:
Else
End If
'将地址调整为4位
If Len(TxtBitAddress.Text) <> 4 Then
Select Case Len(TxtBitAddress.Text)
Case 1
TxtBitAddress.Text = "0" + "0" + "0" + TxtBitAddress.Text
Case 2
TxtBitAddress.Text = "0" + "0" + TxtBitAddress.Text
Case 3
TxtBitAddress.Text = "0" + TxtBitAddress.Text
End Select
End If
'地址和校验
Sum = &H37
For i = 1 To 4
Sum = Sum + Asc(Mid(TxtBitAddress.Text, i, 1))
Next i
Sum = Sum + 3
sumstring = Hex(Sum)
sumstring2 = Right(sumstring, 2)
FrmMain.MSComm1.PortOpen = True
FrmMain.MSComm1.Output = Chr(&H2) + Chr(&H37) 'STX CMD 7
FrmMain.MSComm1.Output = TxtBitAddress.Text
FrmMain.MSComm1.Output = Chr(3) 'ETX
FrmMain.MSComm1.Output = sumstring2 'SUM
'接收应答:
time1 = Timer
Do
DoEvents
Loop Until FrmMain.MSComm1.InBufferCount >= 1 Or (Timer - time1) > 10
instring = FrmMain.MSComm1.Input
If (Timer - time1) > 10 Then
MsgBox "PLC没有响应!"
Else
If instring = Chr(6) Then
MsgBox "数据传输成功!"
Else
If instring = Chr(&H15) Then
MsgBox "数据传输失败!请重试"
Else
End If
End If
End If
FrmMain.MSComm1.PortOpen = False
end1:
End Sub
Private Sub Command1_Click()
FrmBitOnOff.Hide
End Sub
Private Sub Form_Load()
Left = (Screen.Width - Width) / 2
Top = (Screen.Height - Height) / 2
End Sub
Private Sub TxtBitAddress_Change()
TxtBitAddress.Text = UCase(TxtBitAddress.Text)
End Sub
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