gujizhi.txt

时间序列分析

F检验最终辨识结果sita为：
na=5
nb=5
a[1]=-1.196308   b[1]=1.085440   
a[2]=0.812111   b[2]=-0.756731   
a[3]=-0.546050   b[3]=0.465258   
a[4]=0.388840   b[4]=-0.287813   
a[5]=-0.124870   b[5]=0.139110   

t1=   51.147201
t2=   3.728916
t3=   268.367237
t4=   79.900946
t5=   1.162277
t6=   0.791375
t7=   0.327056
t8=   0.575776
t9=   1.058208