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<p class=MsoNormal align=left style='text-align:left'><b><span
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mso-hansi-font-family:"Times New Roman";color:blue'>数据结构辅导站</span></b><b><span
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<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'>1.1 试写一个算法，自大到小依次输出顺序读入的三个数X、Y和Z的值。<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'>void<span style="mso-spacerun: yes">
</span>Desceding(int<span style="mso-spacerun: yes"> </span>&x, int <span
style="mso-spacerun: yes"> </span>&y, int<span style="mso-spacerun:
yes"> </span>&z) {<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'><span style="mso-spacerun: yes">
</span>//将x、y和z按从大到小的顺序排列<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'><span style="mso-spacerun: yes">
</span>if (x<y) x←→y;<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'><span style="mso-spacerun: yes">
</span>if (x<z) x←→z;<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:31.5pt;mso-char-indent-count:3.0;
mso-char-indent-size:10.5pt;mso-char-indent-size:10.5pt'><span lang=EN-US
style='font-family:宋体;color:blue'>if (y<z) y←→z; <o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'>}//Desceding<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'>1.2 试编一个算法求一维数组float
a[n]中的所有元素之和。<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'>float sum(float a[], int n) {<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'><span style="mso-spacerun: yes">
</span>// 求数组a[n]中所有元素之和<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'><span style="mso-spacerun: yes">
</span>for (i=0; i<n; ++i) sum+=a[i];<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'><span style="mso-spacerun: yes">
</span>return sum;<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'>}//sum<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'>1.3 分析下列各算法的时间复杂度：<o:p></o:p></span></p>
<p class=MsoNormal><span style='font-family:宋体'>（<span lang=EN-US>1）void
prime(int n){<o:p></o:p></span></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>/* 判断n是否是素数 */<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>for (i=2;
((n%i)!=0)&&(i<sqrt(n)); i++);<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>if i>sqrt(n)
printf("%d is a prime number", n)<span style="mso-spacerun:
yes"> </span><o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>else printf("%d
is not a prime number", n);<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:26.25pt'><span lang=EN-US
style='font-family:宋体'>}/* prime */<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:26.25pt'><span lang=EN-US
style='font-family:宋体'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:26.25pt'><span style='font-family:宋体;
color:blue'>最坏情况下<span lang=EN-US>O(sqrt(n))<o:p></o:p></span></span></p>
<p class=MsoNormal style='text-indent:26.25pt'><span lang=EN-US
style='font-family:宋体;color:blue'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>(2) float sum1(int n){<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>/* 计算1！+2！+…+n! */<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>p=1; sum1=0;<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>for (i=1; i<=n; ++i){<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>p=p*i;
sum1=sum1+p<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>}<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体'>}/* sum1 */<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'>O(n)<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt'><span lang=EN-US
style='font-family:宋体;color:blue'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'>(3) float sum2(int
n){<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>/* 计算1！+2！+…+n! */<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt;mso-char-indent-count:2.0;
mso-char-indent-size:10.5pt;mso-char-indent-size:10.5pt'><span lang=EN-US
style='font-family:宋体'>sum2=0;<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>for (i=1; i<=n; ++i){<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>p=1;<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>for (j=1;
j<=i; ++j) p=p*j;<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>sum2=sum2+p;<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>}<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>}/* sum2 */<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span><o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体;color:blue'><span
style="mso-spacerun: yes"> </span>O(n<sup>2</sup>)<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体;color:blue'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'>(4) void sort(int
a[],int n){<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>/* 将数组a中的元素按自小到大的顺序排列 */<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>for (i=1; i<=n-1; ++i){<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>k=i;<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>for (j=i+1;
j<=n; ++j) if (a[j]<a[k]) k=j;<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>if (k<>j)
{x=a[i];a[i]=a[k];a[k]=x;}<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>}<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>}/* sort */<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:21.0pt;mso-char-indent-count:2.0;
mso-char-indent-size:10.5pt;mso-char-indent-size:10.5pt'><span lang=EN-US
style='font-family:宋体;color:blue'>O(n<sup>2</sup>)<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:31.5pt'><span lang=EN-US
style='font-family:宋体'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal><span style='font-family:宋体'>（<span lang=EN-US>5）void
matrimult(a[m][n],b[n][l],c[m][l],int m,int n,int l){<o:p></o:p></span></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>/* a为m×n阶的矩阵，b为n×l阶的矩阵，c为m×l阶的矩阵
*/<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>/* 计算c=a*b */<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>for (i=1; i<=m;
++i)<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>for
(j=1; j<=l; ++j)<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun:
yes">
</span>c[i,j]=0;<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>for (i=1; i<=m;
++i)<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun: yes"> </span>for
(j=1; j<=l; ++j)<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun:
yes"> </span>for
(k=1; k<=n; ++k)<o:p></o:p></span></p>
<p class=MsoNormal><span lang=EN-US style='font-family:宋体'><span
style="mso-spacerun:
yes">
</span>c[i,j]=c[i,j]+a[i,k]*b[k,i];<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:26.25pt'><span lang=EN-US
style='font-family:宋体'>}/* matrimult */<o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:26.25pt'><span lang=EN-US
style='font-family:宋体'><![if !supportEmptyParas]> <![endif]><o:p></o:p></span></p>
<p class=MsoNormal style='text-indent:26.25pt'><span lang=EN-US
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