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📄 mod.t

📁 UNIX下perl实现代码
💻 T
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#!./perl# $RCSfile: mod.t,v $$Revision: 4.1 $$Date: 92/08/07 18:27:11 $print "1..12\n";print "ok 1\n" if 1;print "not ok 1\n" unless 1;print "ok 2\n" unless 0;print "not ok 2\n" if 0;1 && (print "not ok 3\n") if 0;1 && (print "ok 3\n") if 1;0 || (print "not ok 4\n") if 0;0 || (print "ok 4\n") if 1;$x = 0;do {$x[$x] = $x;} while ($x++) < 10;if (join(' ',@x) eq '0 1 2 3 4 5 6 7 8 9 10') {	print "ok 5\n";} else {	print "not ok 5 @x\n";}$x = 15;$x = 10 while $x < 10;if ($x == 15) {print "ok 6\n";} else {print "not ok 6\n";}$y[$_] = $_ * 2 foreach @x;if (join(' ',@y) eq '0 2 4 6 8 10 12 14 16 18 20') {	print "ok 7\n";} else {	print "not ok 7 @y\n";}open(foo,'./TEST') || open(foo,'TEST') || open(foo,'t/TEST');$x = 0;$x++ while <foo>;print $x > 50 && $x < 1000 ? "ok 8\n" : "not ok 8\n";$x = -0.5;print "not " if scalar($x) < 0 and $x >= 0;print "ok 9\n";print "not " unless (-(-$x) < 0) == ($x < 0);print "ok 10\n";print "ok 11\n" if $x < 0;print "not ok 11\n" unless $x < 0;print "ok 12\n" unless $x > 0;print "not ok 12\n" if $x > 0;

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