mypn.cpp

产生PN码的源程序. 没有解压密码. 希望多提意见哦.

#include <stdio.h>
#include <fstream.h>
#include <stdlib.h>
#define MYPNLEN 4000000
#define REGLEN 32

unsigned int ap(unsigned int a,unsigned int b);
void shift(void);
void youcheng();
unsigned int A,B,temp,stemp;
unsigned int outdata[MYPNLEN];
unsigned int ab[REGLEN];
unsigned int c[REGLEN]={0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1};
int YC[50];

void main()
{
	FILE *stream;
	stream = fopen( "mypn", "w+t" );
	
	int i,k,kk;
	kk=1;
	A=19434;B=105;
	temp=B&1;
	for (i=0;i<MYPNLEN;i++)
	{
/*		unsigned int ttt;
		ttt=A+1;
		if (REGLEN<32) ttt=ttt&((kk<<REGLEN)-1);
		if (A==0) A+=2;
		if (ttt==0) A+=2;
		ttt=B+1;
		if (REGLEN<32) ttt=ttt&((kk<<REGLEN)-1);
		if (B==0) B+=2;
		if (ttt==0) B+=2;
*/
		if (temp==0) 
		{
			B=A^B;
			if (REGLEN<32) B=B&((kk<<REGLEN)-1);
		}
		else
		{
			A=A^B;
			if (REGLEN<32) A=A&((kk<<REGLEN)-1);
		}
		shift();
		temp=B&1;
		cout<<temp;
		outdata[i]=temp;
	}

//输出，平衡性
	k=0;
	for (i=0;i<MYPNLEN;i++)
	{
		fwrite( &outdata[i], sizeof( int ), 1, stream );
		if (outdata[i]==1) k++;
	}
	fclose( stream );
	cout<<"\n1的个数"<<k<<"\n";

//游程特性：
	youcheng();
	for (i=1;i<=49;i++)
	{
		cout<<"游程YC"<<i<<"  "<<YC[i]<<"\n";
	}

}

void shift(void)
{
	int i;
	unsigned int tt,kk;
	kk=1;
	if (temp==0) stemp=A;
	else stemp=B;
	for (i=0;i<REGLEN;i++)
	{
		ab[i]=stemp&(kk<<i);
		ab[i]=(ab[i]>>i);
	}
	tt=ab[0]*c[0];
	for (i=0;i<(REGLEN-1);i++)
	{
		tt=ap(tt,ab[i+1]*c[i+1]);
	}
	stemp=(stemp<<1);
	if (REGLEN<32) stemp=stemp&((kk<<REGLEN)-1);
	stemp=stemp|tt;
	if (temp==0) A=stemp;
	else B=stemp;
}

unsigned int ap(unsigned int a,unsigned int b)
{
	unsigned int x,y,z;
	x=a;y=b;
	if ((x+y)==1) z=1;
	else z=0;
	return z;
}

void youcheng()
{
	int a,nyc;
	unsigned int temp1;
	temp1=outdata[0];nyc=0;
	for (a=0;a<=49;a++) YC[a]=0;
	for (a=0;a<=(MYPNLEN-1);a++)
	{if (outdata[a]==temp1) nyc=nyc+1;
	 else
		{temp1=outdata[a];
		 YC[nyc]=YC[nyc]+1;
		 nyc=1;
		}
	}
}