e820test.c

来自「linux内核」· C语言 代码 · 共 90 行

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#ident "$Id$"/* ----------------------------------------------------------------------- * *    *   Copyright 2001-2003 H. Peter Anvin - All Rights Reserved * *   This program is free software; you can redistribute it and/or modify *   it under the terms of the GNU General Public License as published by *   the Free Software Foundation, Inc., 53 Temple Place Ste 330, *   Boston MA 02111-1307, USA; either version 2 of the License, or *   (at your option) any later version; incorporated herein by reference. * * ----------------------------------------------------------------------- *//* * e820hack.c * * Test of INT 15:E820 canonicalization/manipulation routine */#include <string.h>#include <stdio.h>#include <stdlib.h>#include <inttypes.h>#include "e820.h"void *sys_bounce;		/* Dummy */extern void parse_mem(void);extern uint32_t dos_mem, low_mem, high_mem;void __attribute__((noreturn)) die(void){  abort();}void printranges(void) {  int i;  for ( i = 0 ; i < nranges ; i++ ) {    printf("%016llx %016llx %d\n",	   ranges[i].start,	   ranges[i+1].start - ranges[i].start,	   ranges[i].type);  }}int main(void){  uint64_t start, len;  uint32_t type;  char line[BUFSIZ], *p;  e820map_init();  printranges();  while ( fgets(line, BUFSIZ, stdin) ) {    p = strchr(line, ':');    p = p ? p+1 : line;    if ( sscanf(p, " %llx %llx %d", &start, &len, &type) == 3 ) {      putchar('\n');       printf("%016llx %016llx %d <-\n", start, len, type);      putchar('\n');       insertrange(start, len, type);      printranges();     }  }  parse_mem();  putchar('\n');  printf("DOS  mem = %#10x (%u K)\n", dos_mem, dos_mem >> 10);  printf("Low  mem = %#10x (%u K)\n", low_mem, low_mem >> 10);  printf("High mem = %#10x (%u K)\n", high_mem, high_mem >> 10);  putchar('\n');  /* Now, steal a chunk (2K) of DOS memory and make sure it registered OK */  insertrange(dos_mem-2048, 2048, 2); /* Type 2 = reserved */    printranges();  parse_mem();  putchar('\n');  printf("DOS  mem = %#10x (%u K)\n", dos_mem, dos_mem >> 10);  printf("Low  mem = %#10x (%u K)\n", low_mem, low_mem >> 10);  printf("High mem = %#10x (%u K)\n", high_mem, high_mem >> 10);  putchar('\n');  return 0;}

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