📄 sqrt.c
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/* diskmodel (version 1.0) * Authors: John Bucy, Greg Ganger * Contributors: John Griffin, Jiri Schindler, Steve Schlosser * * Copyright (c) of Carnegie Mellon University, 2001, 2002, 2003. * * This software is being provided by the copyright holders under the * following license. By obtaining, using and/or copying this * software, you agree that you have read, understood, and will comply * with the following terms and conditions: * * Permission to reproduce, use, and prepare derivative works of this * software is granted provided the copyright and "No Warranty" * statements are included with all reproductions and derivative works * and associated documentation. This software may also be * redistributed without charge provided that the copyright and "No * Warranty" statements are included in all redistributions. * * NO WARRANTY. THIS SOFTWARE IS FURNISHED ON AN "AS IS" BASIS. * CARNEGIE MELLON UNIVERSITY MAKES NO WARRANTIES OF ANY KIND, EITHER * EXPRESSED OR IMPLIED AS TO THE MATTER INCLUDING, BUT NOT LIMITED * TO: WARRANTY OF FITNESS FOR PURPOSE OR MERCHANTABILITY, EXCLUSIVITY * OF RESULTS OR RESULTS OBTAINED FROM USE OF THIS SOFTWARE. CARNEGIE * MELLON UNIVERSITY DOES NOT MAKE ANY WARRANTY OF ANY KIND WITH * RESPECT TO FREEDOM FROM PATENT, TRADEMARK, OR COPYRIGHT * INFRINGEMENT. COPYRIGHT HOLDERS WILL BEAR NO LIABILITY FOR ANY USE * OF THIS SOFTWARE OR DOCUMENTATION. */// #include <sys/types.h>// #include <math.h>#include "dm_config.h"// bucy// really simple; does binary search of the square root space;// square roots must be in [1,65536]uint32_t sqrt32(uint32_t x) { int c; uint32_t old = 0, result = 32767; if(x == 0) return 0; else if(x == 1) return 1; for(c = 0; c <= 16; c++) { uint32_t xsq = result * result; if((xsq <= x ) && (((result + 1) * (result + 1)) > x)) { return result; } old = result; if(xsq > x) { result -= (1 << (15 - c)); } else { result += (result == 65535 ? 0 : (1 << (15 - c))); }/* printf("%d -> %d\n", old, result); */ } return result;}uint64_t sqrt64(uint64_t x) { int c; uint64_t old = 0, result = 2147483647; if(x == 0) return 0; else if(x == 1) return 1; for(c = 0; c <= 32; c++) { uint64_t xsq = result * result; if((xsq <= x ) && (((result + 1) * (result + 1)) > x)) { return result; } old = result; if(xsq > x) { result -= ((uint64_t)1 << (31 - c)); } else { result += (result == 2147483647 ? 0 : ((uint64_t)1 << (31 - c))); } } return result;}
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