xfrprmn.c

来自「适合大型数值计算代码 现在网络上已经找不到了 购买需要20$」· C语言 代码 · 共 52 行

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/* Driver for routine frprmn */#include <stdio.h>#include <math.h>#define NRANSI#include "nr.h"#include "nrutil.h"#define NDIM 3#define FTOL 1.0e-6#define PIO2 1.5707963float func(float x[]){	return 1.0-bessj0(x[1]-0.5)*bessj0(x[2]-0.5)*bessj0(x[3]-0.5);}void dfunc(float x[],float df[]){	df[1]=bessj1(x[1]-0.5)*bessj0(x[2]-0.5)*bessj0(x[3]-0.5);	df[2]=bessj0(x[1]-0.5)*bessj1(x[2]-0.5)*bessj0(x[3]-0.5);	df[3]=bessj0(x[1]-0.5)*bessj0(x[2]-0.5)*bessj1(x[3]-0.5);}int main(void){	int iter,k;	float angl,fret,*p;	p=vector(1,NDIM);	printf("Program finds the minimum of a function\n");	printf("with different trial starting vectors.\n");	printf("True minimum is (0.5,0.5,0.5)\n");	for (k=0;k<=4;k++) {		angl=PIO2*k/4.0;		p[1]=2.0*cos(angl);		p[2]=2.0*sin(angl);		p[3]=0.0;		printf("\nStarting vector: (%6.4f,%6.4f,%6.4f)\n",			p[1],p[2],p[3]);		frprmn(p,NDIM,FTOL,&iter,&fret,func,dfunc);		printf("Iterations: %3d\n",iter);		printf("Solution vector: (%6.4f,%6.4f,%6.4f)\n",			p[1],p[2],p[3]);		printf("Func. value at solution %14f\n",fret);	}	free_vector(p,1,NDIM);	return 0;}#undef NRANSI

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