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📄 xfixrts.c

📁 适合大型数值计算代码 现在网络上已经找不到了 购买需要20$
💻 C
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/* Driver for routine fixrts */#include <stdio.h>#define NRANSI#include "nr.h"#include "complex.h"#define NPOLES 6#define NP1 (NPOLES+1)#define ONE Complex(1.0,0.0)#define TRUE 1int main(void){	int i,polish=TRUE;	static float d[NP1]=		{0.0,6.0,-15.0,20.0,-15.0,6.0,0.0};	fcomplex zcoef[NP1],zeros[NP1],z1,z2;	/* finding roots of (z-1.0)^6=1.0 */	/* first write roots */	zcoef[NPOLES]=ONE;	for (i=NPOLES-1;i>=0;i--)		zcoef[i] = Complex(-d[NPOLES-i],0.0);	zroots(zcoef,NPOLES,zeros,polish);	printf("Roots of (z-1.0)^6 = 1.0\n");	printf("%24s %27s \n","Root","(z-1.0)^6");	for (i=1;i<=NPOLES;i++) {		z1=Csub(zeros[i],ONE);		z2=Cmul(z1,z1);		z1=Cmul(z1,z2);		z1=Cmul(z1,z1);		printf("%6d %12.6f %12.6f %12.6f %12.6f\n",			i,zeros[i].r,zeros[i].i,z1.r,z1.i);	}	/* now fix them to lie within unit circle */	fixrts(d,NPOLES);	/* check results */	zcoef[NPOLES]=ONE;	for (i=NPOLES-1;i>=0;i--)		zcoef[i] = Complex(-d[NPOLES-i],0.0);	zroots(zcoef,NPOLES,zeros,polish);	printf("\nRoots reflected in unit circle\n");	printf("%24s %27s \n","Root","(z-1.0)^6");	for (i=1;i<=NPOLES;i++) {		z1=Csub(zeros[i],ONE);		z2=Cmul(z1,z1);		z1=Cmul(z1,z2);		z1=Cmul(z1,z1);		printf("%6d %12.6f %12.6f %12.6f %12.6f\n",			i,zeros[i].r,zeros[i].i,z1.r,z1.i);	}	return 0;}#undef NRANSI

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