antenna1.mes~orig
来自「sqp程序包。用sqp算法实现非线性约束的优化求解」· MES~ORIG 代码 · 共 80 行
MES~ORIG
80 行
donlp2, v3, 05/29/98, copyright P. SpellucciThu Feb 24 16:52:57 2000antenna1step=1no update since dg=0step=2no update since dg=0step=3no update since dg=0step=4no update since dg=0step=5no update since dg=0step=6rankdeficiency of grad's of active constr.!on the basis of delmin!step=6rankdeficiency of grad's of active constr.! del= 5.000000000000000e-08step=6rankdeficiency of grad's of active constr.! del= 1.000000000000000e-03step=8rankdeficiency of grad's of active constr.!on the basis of delmin!step=8rankdeficiency of grad's of active constr.! del= 2.007093138093704e-03step=8rankdeficiency of grad's of active constr.! del= 2.007093138093704e-03step=9rankdeficiency of grad's of active constr.!on the basis of delmin!step=9rankdeficiency of grad's of active constr.! del= 1.624395463710558e-03step=9rankdeficiency of grad's of active constr.! del= 1.624395463710558e-03step=10rankdeficiency of grad's of active constr.!on the basis of delmin!step=10rankdeficiency of grad's of active constr.! del= 2.958664565506313e-03step=10rankdeficiency of grad's of active constr.! del= 2.958664565506313e-03step=11rankdeficiency of grad's of active constr.!on the basis of delmin!step=11rankdeficiency of grad's of active constr.! del= 7.686989551459435e-04step=11rankdeficiency of grad's of active constr.! del= 1.000000000000000e-03step=12rankdeficiency of grad's of active constr.!on the basis of delmin!step=12rankdeficiency of grad's of active constr.! del= 3.726811798437215e-04step=12rankdeficiency of grad's of active constr.! del= 1.000000000000000e-03step=13rankdeficiency of grad's of active constr.! del= 1.000000000000000e-03step=14rankdeficiency of grad's of active constr.! del= 1.000000000000000e-03step=15rankdeficiency of grad's of active constr.! del= 1.000000000000000e-03step=16rankdeficiency of grad's of active constr.! del= 1.000000000000000e-03
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