xt3-13-2.cpp

最新版谭浩强《c++语言程序设计》所有习题的原代码

#include <iostream>
using namespace std;
int main ()
{long i;
 float bonus,bon1,bon2,bon4,bon6,bon10;
 int c;
 bon1=100000*0.1;
 bon2=bon1+100000*0.075;
 bon4=bon2+200000*0.05;
 bon6=bon4+200000*0.03;
 bon10=bon6+400000*0.015;
 cout<<"enter i:";
 cin>>i;
 c=i/100000;
 if (c>10)  c=10;
 switch(c)
  {case 0: bonus=i*0.1; break;
   case 1: bonus=bon1+(i-100000)*0.075; break;
   case 2:
   case 3: bonus=bon2+(i-200000)*0.05;break;
   case 4:
   case 5: bonus=bon4+(i-400000)*0.03;break;
   case 6:
   case 7:
   case 8:
   case 9: bonus=bon6+(i-600000)*0.015; break;
   case 10: bonus=bon10+(i-1000000)*0.01;
   }
  cout<<"bonus="<<bonus<<endl;
  return 0;
}