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📄 inchcvrt.c

📁 国外网站上的一些精典的C程序
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/***  Convert English measurement units****  Takes command line arguments in inches and converts to:****  1. feet and inches (expressed as floating point)**  2. feet and inches (expressed as fraction)****  public domain demo by Bob Stout**  uses ROUND.H from SNIPPETS*/#include <stdio.h>#include <stdlib.h>#include <math.h>#include "round.h"#define BASE 64.0void cnvrt_inches(double  input,                  double *feet,                  double *inches,                  double *dec_inches,                  double *num_inches,                  double *den_inches){      /*      **  Split feet and inches      */      *feet   = floor(input / 12.0);      *inches = fmod(input, 12.0);      /*      **  Get integer inches and fractions      */      *num_inches = modf(*inches, dec_inches) * BASE;      *num_inches = fround(*num_inches, 0);      if (0.0 == *num_inches)            return;      /*      **  Reduce fractions to lowest common denominator      */      for (*den_inches = BASE;            0.0 == fmod(*num_inches, 2.0);            *den_inches /= 2.0, *num_inches /= 2.0)      {            ;      }}main(int argc, char *argv[]){      double arg, feet, inches, dec, num, den, dummy;      while (--argc)      {            arg = atof(*(++argv));            cnvrt_inches(arg, &feet, &inches, &dec, &num, &den);            printf("%f Inches = %d' %.5f\" or %d' %d",                  arg, (int)feet, inches, (int)feet, (int)dec);            if (0.0 == num)                  puts("\"");            else            {                  printf("-%d/%d\"", (int)num, (int)den);                  if (modf(num, &dummy))                        puts(" (approx.)");                  else  puts("");            }      }      return EXIT_SUCCESS;}

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