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📄 fc_tanker.m

📁 一个用MATLAB编写的优化控制工具箱
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% Fuzzy Control System for a Tanker Ship%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% By: Kevin Passino % Version: 4/15/99%% Notes: This program has evolved over time and uses programming % ideas of Andrew Kwong, Scott Brown, and Brian Klinehoffer.%% This program simulates a fuzzy control system for a tanker% ship.  It has a fuzzy controller with two inputs, the error% in the ship heading (e) and the change in that error (c).  The output% of the fuzzy controller is the rudder input (delta).  We want the % tanker ship heading (psi) to track the reference input heading% (psi_r).  We simulate the tanker as a continuous time system % that is controlled by a fuzzy controller that is implemented on% a digital computer with a sampling interval of T.  %% This program can be used to illustrate:%  - How to code a fuzzy controller (for two inputs and one output, %    illustrating some approaches to simplify the computations, for%    triangular membership functions, and either center-of-gravity or%    center-average defuzzification).%  - How to tune the input and output gains of a fuzzy controller.%  - How changes in plant conditions ("ballast" and "full") %    can affect performance.%  - How sensor noise (heading sensor noise), plant disturbances%    (wind hitting the side of the ship), and plant operating%    conditions (ship speed) can affect performance.%  - How improper choice of the scaling gains can result in %    oscillations (limit cycles).%  - How an improper choice of the scaling gains (or rule base) can%    result in an unstable system.%  - The shape of the nonlinearity implemented by the fuzzy controller%    by plotting the input-output map of the fuzzy controller.%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%clear		% Clear all variables in memory% Initialize ship parameters % (can test two conditions, "ballast" or "full"):ell=350;			% Length of the ship (in meters)u=5;				% Nominal speed (in meters/sec)%u=3;               % A lower speed where the ship is more difficult to controlabar=1;             % Parameters for nonlinearitybbar=1;% The parameters for the tanker under "ballast" conditions % (a heavy ship) are:K_0=5.88;tau_10=-16.91;tau_20=0.45;tau_30=1.43;% The parameters for the tanker under "full" conditions (a ship% that weighs less than one under "ballast" conditions) are:%K_0=0.83;%tau_10=-2.88;%tau_20=0.38;%tau_30=1.07;% Some other parameters are:K=K_0*(u/ell);tau_1=tau_10*(ell/u);tau_2=tau_20*(ell/u);tau_3=tau_30*(ell/u);% Initialize parameters for the fuzzy controllernume=11; 	% Number of input membership functions for the e 			% universe of discourse (can change this but must also			% change some variables below if you make such a change)numc=11; 	% Number of input membership functions for the c 			% universe of discourse (can change this but must also			% change some variables below if you make such a change)% Next, we define the scaling gains for tuning membership functions for % universes of discourse for e, change in e (what we call c) and % delta.  These are g1, g2, and g0, respectively% These can be tuned to try to improve the performance. % First guess: g1=1/pi;,g2=100;,g0=8*pi/18; % Chosen since: 		% g1: The heading error is at most 180 deg (pi rad) 		% g2: Just a guess - that ship heading will change at most		%     by 0.01 rad/sec (0.57 deg/sec)		% g0: Since the rudder is constrained to move between +-80 deg% Tuning:g1=1/pi;,g2=200;,g0=8*pi/18; % Try to reduce the overshootg1=2/pi;,g2=250;,g0=8*pi/18; % Try to speed up the response a bit but to do this 							 % have to raise g2 a bit to avoid overshoot. Take these							 % as "good" tuned values.  %g1=2/pi;,g2=0.000001;,g0=2000*pi/18; % Values tuned to get an oscillation (limit									  % cycle) for COG, ballast,									  % and nominal speed with no sensor 									  % noise or rudder disturbance):									  % g1: Leave as before								      % g2: Essentially turn off the derivative gain									  %     since this help induce an oscillation									  % g0: Make this big to force the limit cycle									  % In this case simulate for 16,000 sec.%g1=2/pi;,g2=250;,g0=-8*pi/18;       % Values tuned to get an instability									% g0: Make this negative so that when there									% is an error the rudder will drive the 									% heading in the direction to increase the error% Next, define some parameters for the membership functionswe=0.2*(1/g1);	  	% we is half the width of the triangular input membership 	% function bases (note that if you change g0, the base width	% will correspondingly change so that we always end	% up with uniformly distributed input membership functions)	% Note that if you change nume you will need to adjust the 	% "0.2" factor if you want membership functions that 	% overlap in the same way.wc=0.2*(1/g2);        	% Similar to we but for the c universe of discoursebase=0.4*g0;      	% Base width of output membership fuctions of the fuzzy 	% controller% Place centers of membership functions of the fuzzy controller:% Centers of input membership functions for the e universe of% discourse of fuzzy controller (a vector of centers)ce=[-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1]*(1/g1);% Centers of input membership functions for the c universe of% discourse of fuzzy controller (a vector of centers)cc=[-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1]*(1/g2);% This next matrix specifies the rules of the fuzzy controller.  % The entries are the centers of the output membership functions.  % This choice represents just one guess on how to synthesize % the fuzzy controller.  Notice the regularity % of the pattern of rules.  Notice that it is scaled by g0, the % output scaling factor, since it is a normalized rule base.% The rule base can be tuned to try to improve performance.rules=[1    1     1     1    1     1    0.8   0.6   0.3    0.1     0;  	   1    1     1     1    1   0.8    0.6   0.3   0.1    0     -0.1;	   1    1     1     1   0.8  0.6    0.3   0.1   0     -0.1   -0.3;	   1    1     1   0.8   0.6  0.3    0.1    0    -0.1   -0.3  -0.6;	   1    1   0.8   0.6   0.3  0.1     0   -0.1   -0.3   -0.6  -0.8;	   1  0.8   0.6   0.3   0.1   0    -0.1  -0.3   -0.6   -0.8   -1;	 0.8  0.6   0.3   0.1    0   -0.1  -0.3  -0.6   -0.8   -1     -1;	 0.6  0.3   0.1    0   -0.1  -0.3  -0.6  -0.8   -1     -1     -1;	 0.3  0.1    0   -0.1  -0.3  -0.6  -0.8   -1    -1     -1     -1;	 0.1   0   -0.1  -0.3  -0.6  -0.8   -1    -1    -1     -1     -1;	   0 -0.1  -0.3  -0.6  -0.8  -1     -1    -1    -1     -1     -1]*g0;% Now, you can proceed to do the simulation or simply view the nonlinear% surface generated by the fuzzy controller. flag1=input('\n Do you want to simulate the \n fuzzy control system \n for the tanker?  \n (type 1 for yes and 0 for no) ');if flag1==1, 	% Next, we initialize the simulation:t=0; 		% Reset time to zeroindex=1;	% This is time's index (not time, its index).  tstop=4000;	% Stopping time for the simulation (in seconds)step=1;     % Integration step sizeT=10;		% The controller is implemented in discrete time and			% this is the sampling time for the controller.			% Note that the integration step size and the sampling			% time are not the same.  In this way we seek to simulate			% the continuous time system via the Runge-Kutta method and			% the discrete time fuzzy controller as if it were			% implemented by a digital computer.  Hence, we sample			% the plant output every T seconds and at that time			% output a new value of the controller output.counter=10;	% This counter will be used to count the number of integration			% steps that have been taken in the current sampling interval.			% Set it to 10 to begin so that it will compute a fuzzy controller			% output at the first step.			% For our example, when 10 integration steps have been			% taken we will then we will sample the ship heading			% and the reference heading and compute a new output			% for the fuzzy controller.  eold=0;     % Initialize the past value of the error (for use            % in computing the change of the error, c).  Notice            % that this is somewhat of an arbitrary choice since             % there is no last time step.  The same problem is            % encountered in implementation.  x=[0;0;0];	% First, set the state to be a vector            x(1)=0;		% Set the initial heading to be zerox(2)=0;		% Set the initial heading rate to be zero.  			% We would also like to set x(3) initially but this			% must be done after we have computed the output			% of the fuzzy controller.  In this case, by			% choosing the reference trajectory to be 			% zero at the beginning and the other initial conditions			% as they are, and the fuzzy controller as designed,			% we will know that the output of the fuzzy controller			% will start out at zero so we could have set 			% x(3)=0 here.  To keep things more general, however, 			% we set the intial condition immediately after 			% we compute the first controller output in the 			% loop below.psi_r_old=0; % Initialize the reference trajectory% Next, we start the simulation of the system.  This is the main % loop for the simulation of fuzzy control system.while t <= tstop% First, we define the reference input psi_r  (desired heading).if t<100, psi_r(index)=0; end    			% Request heading of 0 degif t>=100, psi_r(index)=45*(pi/180); end     % Request heading of 45 degif t>2000, psi_r(index)=0; end      			% Then request heading of 0 deg%if t>4000, psi_r(index)=45*(pi/180); end     % Then request heading of 45 deg%if t>6000, psi_r(index)=0; end      			% Then request heading of 0 deg%if t>8000, psi_r(index)=45*(pi/180); end     % Then request heading of 45 deg%if t>10000, psi_r(index)=0; end      			% Then request heading of 0 deg%if t>12000, psi_r(index)=45*(pi/180); end     % Then request heading of 45 deg% Next, suppose that there is sensor noise for the heading sensor with that is% additive, with a uniform distribution on [- 0.01,+0.01] deg.%s(index)=0.01*(pi/180)*(2*rand-1);s(index)=0;					  % This allows us to remove the noise.psi(index)=x(1)+s(index);     % Heading of the ship (possibly with sensor noise).if counter == 10,  % When the counter reaches 10 then execute the 				   % fuzzy controllercounter=0; 			% First, reset the counter% Fuzzy controller calculations:% First, for the given fuzzy controller inputs we determine% the extent at which the error membership functions % of the fuzzy controller are on (this is the fuzzification part).c_count=0;,e_count=0;   % These are used to count the number of 						% non-zero mf certainities of e and ce(index)=psi_r(index)-psi(index);				% Calculates the error input for the fuzzy controller			c(index)=(e(index)-eold)/T; % Sets the value of ceold=e(index);   % Save the past value of e for use in the above				 % computation the next time around the loop				% The following if-then structure fills the vector mfe % with the certainty of each membership fucntion of e for the % current input e.  We use triangular membership functions.	if e(index)<=ce(1)		% Takes care of saturation of the left-most 					        % membership function         mfe=[1 0 0 0 0 0 0 0 0 0 0]; % i.e., the only one on is the          							  % left-most one	 e_count=e_count+1;,e_int=1; 	  %  One mf on, it is the 	 								  % left-most one.	elseif e(index)>=ce(nume)				  % Takes care of saturation 									  % of the right-most mf	 mfe=[0 0 0 0 0 0 0 0 0 0 1];	 e_count=e_count+1;,e_int=nume; % One mf on, it is the 	 								% right-most one	else      % In this case the input is on the middle part of the 			  % universe of discourse for e			  % Next, we are going to cycle through the mfs to 			  % find all that are on	   for i=1:nume		 if e(index)<=ce(i)		  mfe(i)=max([0 1+(e(index)-ce(i))/we]);   		  				% In this case the input is to the 		  				% left of the center ce(i) and we compute						% the value of the mf centered at ce(i)						% for this input e			if mfe(i)~=0					% If the certainty is not equal to zero then say 				% that have one mf on by incrementing our count			 e_count=e_count+1;			 e_int=i;	% This term holds the index last entry 			 			% with a non-zero term			end		 else 		  mfe(i)=max([0,1+(ce(i)-e(index))/we]); 		  						% In this case the input is to the		  						% right of the center ce(i)			if mfe(i)~=0			 e_count=e_count+1;   			 e_int=i;  % This term holds the index of the 			 		   % last entry with a non-zero term			end		 end		end	end% The following if-then structure fills the vector mfc with the % certainty of each membership fucntion of the c% for its current value (to understand this part of the code see the above % similar code for computing mfe).  Clearly, it could be more efficient to% make a subroutine that performs these computations for each of % the fuzzy system inputs.	if c(index)<=cc(1)	% Takes care of saturation of left-most mf         mfc=[1 0 0 0 0 0 0 0 0 0 0];	 c_count=c_count+1;	 c_int=1;   	elseif c(index)>=cc(numc)					        % Takes care of saturation of the right-most mf	 mfc=[0 0 0 0 0 0 0 0 0 0 1];	 c_count=c_count+1; 	 c_int=numc;	else		for i=1:numc		 if c(index)<=cc(i)  		  mfc(i)=max([0,1+(c(index)-cc(i))/wc]);			if mfc(i)~=0			 c_count=c_count+1;			 c_int=i;  	    % This term holds last entry 			 		     	% with a non-zero term			end		 else 		  mfc(i)=max([0,1+(cc(i)-c(index))/wc]);			if mfc(i)~=0			 c_count=c_count+1;			 c_int=i;	% This term holds last entry 			 			% with a non-zero term			end		 end		end

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