9-25.txt

C++完美演绎 经典算法 如 /* 头文件：my_Include.h */ #include <stdio.h> /* 展开C语言的内建函数指令 */ #define PI 3.141

/* 范例：9-25 */
#include <stdio.h>
#include <io.h>
#include <fcntl.h>
#include <stdlib.h>
void gg(int a,int ret)
{
  char *msg[]={"File Exist","Excute","Allow Write", \
	          "","Allow Read","","Read & Write"};
  if(ret==0)
    printf("%12s : Yes!\n",msg[a]);
  if(ret==-1)
    printf("%12s : No!\n",msg[a]);
}
void main(int argc,char *argv[])
{
  int handle;
  int i,ret;
  if((handle=open(argv[1],O_RDONLY))==NULL)
  {
    printf("文件打开错误!\n");
    exit(1);
  }
  printf("FileName: %s\tSize:%d bytes.\n", argv[1],	\ filelength(handle));
  for(i=0;i<7;i++)
  {
    if((i!=3)&&(i!=5))
      gg(i,access(argv[1],i));
  }
  close(handle);
}

程序输出结果：(假设r.txt为一个只读文件，取得文件信息如下)
D:\TC>p9-25 r.txt
	FileName:	r.txt Size:14 bytes.
	File Exist :	Yes!
	Excute :	Yes!
	Allow Write :	No!
	Allow Read :	Yes!
	Read & Write :	No!