📄 一段加密函数(base64).htm
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<TD bgColor=#297dff colSpan=2 height=20><FONT color=#ceffff> →
<A href="http://www.aspsky.net/article/index.asp?classid=2"><FONT
color=#ceffff>ASP技术</FONT></A> >> <A
href="http://www.aspsky.net/article/index.asp?classid=2&Nclassid=5"><FONT
color=#ceffff>安全加密</FONT></A> >> 《一段加密函数(base64)》</FONT></TD></TR>
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<TD align=middle class=p4
colSpan=2><B>一段加密函数(base64)</B></FONT><BR>2002-3-4 动网先锋
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<BLOCKQUOTE><BR>Const sBASE_64_CHARACTERS =
"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
<P></P>
<P><BR>Function Base64encode(ByVal asContents) <BR>Dim lnPosition
<BR>Dim lsResult <BR>Dim Char1 <BR>Dim Char2 <BR>Dim Char3 <BR>Dim
Char4 <BR>Dim Byte1 <BR>Dim Byte2 <BR>Dim Byte3 <BR>Dim SaveBits1
<BR>Dim SaveBits2 <BR>Dim lsGroupBinary <BR>Dim lsGroup64 </P>
<P>If Len(asContents) Mod 3 > 0 Then asContents = asContents
& String(3 - (Len(asContents) Mod 3), " ") <BR>lsResult = ""
</P>
<P>For lnPosition = 1 To Len(asContents) Step 3 <BR>lsGroup64 = ""
<BR>lsGroupBinary = Mid(asContents, lnPosition, 3) </P>
<P>Byte1 = Asc(Mid(lsGroupBinary, 1, 1)): SaveBits1 = Byte1 And 3
<BR>Byte2 = Asc(Mid(lsGroupBinary, 2, 1)): SaveBits2 = Byte2 And
15 <BR>Byte3 = Asc(Mid(lsGroupBinary, 3, 1)) </P>
<P>Char1 = Mid(sBASE_64_CHARACTERS, ((Byte1 And 252) \ 4) + 1, 1)
<BR>Char2 = Mid(sBASE_64_CHARACTERS, (((Byte2 And 240) \ 16) Or
(SaveBits1 * 16) And &HFF) + 1, 1) <BR>Char3 =
Mid(sBASE_64_CHARACTERS, (((Byte3 And 192) \ 64) Or (SaveBits2 *
4) And &HFF) + 1, 1) <BR>Char4 = Mid(sBASE_64_CHARACTERS,
(Byte3 And 63) + 1, 1) <BR>lsGroup64 = Char1 & Char2 &
Char3 & Char4 <BR><BR>lsResult = lsResult + lsGroup64 <BR>Next
</P>
<P>Base64encode = lsResult <BR>End Function
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<BLOCKQUOTE>原作者:shark<BR>来 源:开发者俱乐部<BR>共有4057位读者阅读过此文<BR>【<A
href="http://bbs.aspsky.net/list.asp?boardid=1">发表评论</A>】
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<LI><FONT color=#0772b1>上篇文章</FONT>:<A
href="http://www.aspsky.net/article/list.asp?id=2636">一段加密函数</A>
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