9-29.txt

c++完美演绎源代码

/* 范例：9-29 */
#include <stdio.h>
#include <stdlib.h>
void main(int argc,char *argv[])
{
  FILE *fp1;
  int ch;

  if(argc!=2)
  {
    printf("Syntax Error!\n\tp9-29 filename");
    exit(1);
  }
  if((fp1=fopen(argv[1],"r"))==NULL)
  {
    printf("Read file %s Error!\n",argv[1]);
    exit(1);
  }
  while(!feof(fp1))
  {
    ch = getc(fp1);
    if(ch!=-1)
      putchar(ch);
  }

  fclose(fp1);
}

程序执行结果：
D:\TC>p9-29 new.txt
程序执行结果