msymtrieigenvmainmodule.bas
来自「科学与工程数值计算算法(Visual Basic版)一书的源代码。对科学研究者自」· BAS 代码 · 共 42 行
BAS
42 行
Attribute VB_Name = "MainModule"
Sub Main()
Dim mtxA(5, 5) As Double
Dim mtxQ(5, 5) As Double
Dim mtxT(5, 5) As Double
Dim dblB(5) As Double, dblC(5) As Double
Dim sEigenValue As String, sEigenVector As String
Dim i As Integer
' 原矩阵
mtxA(1, 1) = 10: mtxA(1, 2) = 1: mtxA(1, 3) = 2: mtxA(1, 4) = 3: mtxA(1, 5) = 4
mtxA(2, 1) = 1: mtxA(2, 2) = 9: mtxA(2, 3) = -1: mtxA(2, 4) = 2: mtxA(2, 5) = -3
mtxA(3, 1) = 2: mtxA(3, 2) = -1: mtxA(3, 3) = 7: mtxA(3, 4) = 3: mtxA(3, 5) = -5
mtxA(4, 1) = 3: mtxA(4, 2) = 2: mtxA(4, 3) = 3: mtxA(4, 4) = 12: mtxA(4, 5) = -1
mtxA(5, 1) = 4: mtxA(5, 2) = -3: mtxA(5, 3) = -5: mtxA(5, 4) = -1: mtxA(5, 5) = 15
'求解对称三对角矩阵
Call MSymTri(5, mtxA, mtxQ, mtxT, dblB, dblC)
'求解对称三对角矩阵的特征值和特征向量
If MSymTriEigenv(5, dblB, dblC, mtxQ, 0.000001, 60) Then
' 特征值和特征向量
For i = 1 To 5
sEigenValue = sEigenValue & i & ": " & Format(dblB(i), "######0.0000000") & Chr(13)
sEigenVector = sEigenVector & i & ": " & MatrixColToString(5, i, mtxQ, "######0.0000000") & Chr(13)
Next i
MsgBox "求解成功!" & Chr$(13) & Chr$(13) & _
"原矩阵A" & Chr$(13) & Chr$(13) & _
MatrixToString(5, 5, mtxA, "######0.0000000") & Chr$(13) & _
"特征值" & Chr$(13) & Chr$(13) & _
sEigenValue & Chr$(13) & _
"特征向量" & Chr$(13) & Chr$(13) & _
sEigenVector
Else
MsgBox "求解失败!"
End If
End Sub
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