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'这是一个分别用Bezier曲线和B样条曲线进行曲线拟合的例子
'程序用VB6.0中文版编写
'例子中需要一个窗体和一个按钮(使用默认的名字)
'在本例中,黑色的线条是对坐标系上各点的直接连线
'黄色的线仅对点间连线进行近似拟合,并不通过每一个点,使用的是B样条曲线
'蓝色的线通过除第一个点和最后一个点之外的每一个点,使用的是Bezier曲线
'本程序仅供参考和演示,尚有许多不足之处,只为抛砖引玉。
'DDMM们可以借鉴,高手们也不妨一观,繁请且一笑之,尔后以不屑为此之态随心指点一二,吾恩谢之。
' ——残桓枫雪 敬上
Option Explicit
Private Type Vi '定义点的数据结构
x As Double
y As Double
End Type
Dim Pts(64) As Vi, Ypts(64) As Double '用于Bezier绘制的临时点坐标
Dim Points(3) As Vi, PointsB(3) As Vi
Dim Po(-1 To 100) As Vi
Dim CosNN(158) As Double '用于通过Cos值查表获取角度
'Bezier计算
Private Sub calc_spline(Npts As Integer)
Dim x As Double, dx As Double, ddx As Double, dddx As Double
Dim y As Double, dy As Double, ddy As Double, dddy As Double
Dim i As Integer
Dim dt As Double, dt2 As Double, dt3 As Double
Dim xdt2_term As Double, xdt3_term As Double
Dim ydt2_term As Double, ydt3_term As Double
dt = 1# / (Npts - 1)
dt2 = (dt * dt)
dt3 = (dt2 * dt)
' x 坐标增量计算
xdt2_term = 3 * (Points(2).x - 2 * Points(1).x + Points(0).x)
xdt3_term = Points(3).x + 3 * (-Points(2).x + Points(1).x) - Points(0).x
xdt2_term = dt2 * xdt2_term
xdt3_term = dt3 * xdt3_term
dddx = 6 * xdt3_term
ddx = -6 * xdt3_term + 2 * xdt2_term
dx = xdt3_term - xdt2_term + 3 * dt * (Points(1).x - Points(0).x)
x = Points(0).x
Pts(0).x = Points(0).x
x = x + 0.5
For i = 1 To Npts
ddx = ddx + dddx
dx = dx + ddx
x = x + dx
Pts(i).x = x
Next i
' y 坐标增量计算
ydt2_term = 3 * (Points(2).y - 2 * Points(1).y + Points(0).y)
ydt3_term = Points(3).y + 3 * (-Points(2).y + Points(1).y) - Points(0).y
ydt2_term = dt2 * ydt2_term
ydt3_term = dt3 * ydt3_term
dddy = 6 * ydt3_term
ddy = -6 * ydt3_term + 2 * ydt2_term
dy = ydt3_term - ydt2_term + dt * 3 * (Points(1).y - Points(0).y)
y = Points(0).y
Pts(0).y = Points(0).y
y = y + 0.5
For i = 1 To Npts
ddy = ddy + dddy
dy = dy + ddy
y = y + dy
Pts(i).y = y
Next i
End Sub
'Bezier控制点计算
Private Sub DRC()
Dim Tem(3) As Vi, TemB As Double, JD(1) As Double, JDT(1) As Double, t As Double, t2(1) As Double
'Bezier端点赋值
Points(0).x = PointsB(1).x
Points(0).y = PointsB(1).y
Points(3).x = PointsB(2).x
Points(3).y = PointsB(2).y
'计算Bezier控制点位置
Tem(0).x = PointsB(1).x - PointsB(0).x
Tem(0).y = PointsB(1).y - PointsB(0).y
Tem(1).x = Tem(0).x / Sqr(Tem(0).x * Tem(0).x + Tem(0).y * Tem(0).y)
Tem(0).x = PointsB(2).x - PointsB(1).x
Tem(0).y = PointsB(2).y - PointsB(1).y
Tem(1).y = Tem(0).x / Sqr(Tem(0).x * Tem(0).x + Tem(0).y * Tem(0).y)
t2(0) = 1: t2(1) = 1
For t = 0 To 158
If t2(0) > Abs(Tem(1).x - CosNN(t)) Then
JDT(0) = t / 100
t2(0) = Abs(Tem(1).x - CosNN(t))
End If
If t2(1) > Abs(Tem(1).y - CosNN(t)) Then
JDT(1) = t / 100
t2(1) = Abs(Tem(1).y - CosNN(t))
End If
Next t
JD(0) = (Sgn(PointsB(0).y - PointsB(1).y) * JDT(0) + Sgn(PointsB(1).y - PointsB(2).y) * JDT(1)) / 2
'''''
Tem(0).x = PointsB(3).x - PointsB(2).x
Tem(0).y = PointsB(3).y - PointsB(2).y
Tem(1).x = Tem(0).x / Sqr(Tem(0).x * Tem(0).x + Tem(0).y * Tem(0).y)
Tem(0).x = PointsB(2).x - PointsB(1).x
Tem(0).y = PointsB(2).y - PointsB(1).y
Tem(1).y = Tem(0).x / Sqr(Tem(0).x * Tem(0).x + Tem(0).y * Tem(0).y)
t2(0) = 1: t2(1) = 1
For t = 0 To 158
If t2(0) > Abs(Tem(1).x - CosNN(t)) Then
JDT(0) = t / 100
t2(0) = Abs(Tem(1).x - CosNN(t))
End If
If t2(1) > Abs(Tem(1).y - CosNN(t)) Then
JDT(1) = t / 100
t2(1) = Abs(Tem(1).y - CosNN(t))
End If
Next t
JD(1) = (Sgn(PointsB(2).y - PointsB(3).y) * JDT(0) + Sgn(PointsB(1).y - PointsB(2).y) * JDT(1)) / 2 + 3.14
TemB = (PointsB(2).x - PointsB(1).x) / 2.82
'Bezier控制点赋值
Points(1).x = Cos(JD(0)) * TemB + PointsB(1).x
Points(1).y = -Sin(JD(0)) * TemB + PointsB(1).y
Points(2).x = Cos(JD(1)) * TemB + PointsB(2).x
Points(2).y = -Sin(JD(1)) * TemB + PointsB(2).y
spline (vbBlue)
End Sub
'Bezier绘制
Private Sub spline(color As Long)
Dim i As Integer
Dim C As Long
calc_spline (64)
For i = 1 To 63
Line (Pts(i - 1).x, Pts(i - 1).y)-(Pts(i).x, Pts(i).y), color
Next i
Line (Pts(i - 1).x, Pts(i - 1).y)-(Pts(i).x, Pts(i).y), color
End Sub
'Bezier调用
Private Sub B1(n As Integer, st As Double)
Dim t As Integer
For t = 0 To n - 4
PointsB(0).x = Po(t).x
PointsB(0).y = Po(t).y
PointsB(1).x = Po(t + 1).x
PointsB(1).y = Po(t + 1).y
PointsB(2).x = Po(t + 2).x
PointsB(2).y = Po(t + 2).y
PointsB(3).x = Po(t + 3).x
PointsB(3).y = Po(t + 3).y
DRC
Next t
End Sub
'B样条曲线生成
Private Sub B2(n As Integer, st As Double)
Dim l As Double, x As Double, y As Double, x0 As Double, x1 As Double, x2 As Double, y0 As Double, y1 As Double, y2 As Double
Dim a As Integer
For a = 0 To n - 3
x0 = (Po(a).x + Po(a + 1).x) / 2#
x1 = Po(a + 1).x - Po(a).x
x2 = (Po(a).x - 2 * Po(a + 1).x + Po(a + 2).x) / 2#
y0 = (Po(a).y + Po(a + 1).y) / 2#
y1 = Po(a + 1).y - Po(a).y
y2 = (Po(a).y - 2 * Po(a + 1).y + Po(a + 2).y) / 2#
PSet (x0, y0), vbYellow
For l = 0 To 1 Step st
x = x0 + x1 * l + x2 * l * l
y = y0 + y1 * l + y2 * l * l
Line -(x, y), vbYellow
Next l
Next a
End Sub
Private Sub Command1_Click()
Dim dx As Integer, dy As Integer, t As Integer
Cls
Po(-1).x = Rnd * 40
Po(-1).y = Rnd * 300
PSet (Po(-1).x, Po(-1).y)
For t = 0 To 31
dx = Rnd * 40
dy = Rnd * 300
Po(t).x = Po(t - 1).x + dx
Po(t).y = dy
Line -(Po(t).x, Po(t).y)
Next
Call B2(30, 0.1)
Call B1(30, 0)
End Sub
Private Sub Form_Load()
Dim t As Double, t2 As Double
For t = 0 To 1.58 Step 0.01
CosNN(t2) = Cos(t)
t2 = t2 + 1
Next t
End Sub
For I=0 to 999 Step -1: Money = Money + 1: Next I
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