rsa加密算法在vb中的实现.txt

来自「RSA加密算法在VB中的实现.可以更好的了解RSA加密算法.」· 文本 代码 · 共 209 行

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' RSA加密算法在VB中的实现
        

Public key(1 To 3) As Long 
Private Const base64 = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrst
uvwxyz0123456789+/" 

Public Sub GenKey() 
Dim d As Long, phi As Long, e As Long 
Dim m As Long, x As Long, q As Long 
Dim p As Long 
Randomize 
On Error GoTo top 
top: 
p = Rnd * 1000 \ 1 
If IsPrime(p) = False Then GoTo top 
Sel_q: 
q = Rnd * 1000 \ 1 
If IsPrime(q) = False Then GoTo Sel_q 
n = p * q \ 1 
phi = (p - 1) * (q - 1) \ 1 
d = Rnd * n \ 1 
If d = 0 Or n = 0 Or d = 1 Then GoTo top 
e = Euler(phi, d) 
If e = 0 Or e = 1 Then GoTo top 

x = Mult(255, e, n) 
If Not Mult(x, d, n) = 255 Then 
    DoEvents 
    GoTo top 
ElseIf Mult(x, d, n) = 255 Then 
    key(1) = e 
    key(2) = d 
    key(3) = n 
End If 
End Sub 

Private Function Euler(ByVal a As Long, ByVal b As Long) As Long 
On Error GoTo error2 
r1 = a: r = b 
p1 = 0: p = 1 
q1 = 2: q = 0 
n = -1 
Do Until r = 0 
    r2 = r1: r1 = r 
    p2 = p1: p1 = p 
    q2 = q1: q1 = q 
    n = n + 1 
    r = r2 Mod r1 
    c = r2 \ r1 
    p = (c * p1) + p2 
    q = (c * q1) + q2 
Loop 
s = (b * p1) - (a * q1) 
If s > 0 Then 
    x = p1 
Else 
    x = (0 - p1) + a 
End If 
Euler = x 
Exit Function 

error2: 
Euler = 0 
End Function 

Private Function Mult(ByVal x As Long, ByVal p As Long, ByVal m As Lon
g) As Long 
y = 1 
On Error GoTo error1 
Do While p > 0 
    Do While (p / 2) = (p \ 2) 
        x = (x * x) Mod m 
        p = p / 2 
    Loop 
    y = (x * y) Mod m 
    p = p - 1 
Loop 
Mult = y 
Exit Function 

error1: 
y = 0 
End Function 

Private Function IsPrime(lngNumber As Long) As Boolean 
Dim lngCount As Long 
Dim lngSqr As Long 
Dim x As Long 

    lngSqr = Sqr(lngNumber) ' get the int square root 

    If lngNumber < 2 Then 
IsPrime = False 
Exit Function 
End If 

lngCount = 2 
IsPrime = True 

If lngNumber Mod lngCount = 0& Then 
IsPrime = False 
Exit Function 
End If 

lngCount = 3 

For x& = lngCount To lngSqr Step 2 
If lngNumber Mod x& = 0 Then 
IsPrime = False 
Exit Function 
End If 
Next 
End Function 

Private Function Base64_Encode(DecryptedText As String) As String 
Dim c1, c2, c3 As Integer 
Dim w1 As Integer 
Dim w2 As Integer 
Dim w3 As Integer 
Dim w4 As Integer 
Dim n As Integer 
Dim retry As String 
For n = 1 To Len(DecryptedText) Step 3 
c1 = Asc(Mid$(DecryptedText, n, 1)) 
c2 = Asc(Mid$(DecryptedText, n + 1, 1) + Chr$(0)) 
c3 = Asc(Mid$(DecryptedText, n + 2, 1) + Chr$(0)) 
w1 = Int(c1 / 4) 
w2 = (c1 And 3) * 16 + Int(c2 / 16) 
If Len(DecryptedText) >= n + 1 Then w3 = (c2 And 15) * 4 + Int(c
3 / 64) Else w3 = -1 
      If Len(DecryptedText) >= n + 2 Then w4 = c3 And 63 Else w4 = -1 

      retry = retry + mimeencode(w1) + mimeencode(w2) + mimeencode(w3)
 + mimeencode(w4) 
   Next 
   Base64_Encode = retry 
End Function 

Private Function Base64_Decode(a As String) As String 
Dim w1 As Integer 
Dim w2 As Integer 
Dim w3 As Integer 
Dim w4 As Integer 
Dim n As Integer 
Dim retry As String 

   For n = 1 To Len(a) Step 4 
      w1 = mimedecode(Mid$(a, n, 1)) 
      w2 = mimedecode(Mid$(a, n + 1, 1)) 
      w3 = mimedecode(Mid$(a, n + 2, 1)) 
      w4 = mimedecode(Mid$(a, n + 3, 1)) 
      If w2 >= 0 Then retry = retry + Chr$(((w1 * 4 + Int(w2 / 16)) An
d 255)) 
      If w3 >= 0 Then retry = retry + Chr$(((w2 * 16 + Int(w3 / 4)) An
d 255)) 
      If w4 >= 0 Then retry = retry + Chr$(((w3 * 64 + w4) And 255)) 
   Next 
   Base64_Decode = retry 
End Function 

Private Function mimeencode(w As Integer) As String 
   If w >= 0 Then mimeencode = Mid$(base64, w + 1, 1) Else mimeencode 
= "" 
End Function 

Private Function mimedecode(a As String) As Integer 
   If Len(a) = 0 Then mimedecode = -1: Exit Function 
   mimedecode = InStr(base64, a) - 1 
End Function 

Public Function Encode(ByVal Inp As String, ByVal e As Long, ByVal n A
s Long) As String 
Dim s As String 
s = "" 
m = Inp 

If m = "" Then Exit Function 
s = Mult(CLng(Asc(Mid(m, 1, 1))), e, n) 
For i = 2 To Len(m) 
    s = s & "+" & Mult(CLng(Asc(Mid(m, i, 1))), e, n) 
Next i 
Encode = Base64_Encode(s) 
End Function 

Public Function Decode(ByVal Inp As String, ByVal d As Long, ByVal n A
s Long) As String 
St = "" 
ind = Base64_Decode(Inp) 
For i = 1 To Len(ind) 
    nxt = InStr(i, ind, "+") 
    If Not nxt = 0 Then 
        tok = Val(Mid(ind, i, nxt)) 
    Else 
        tok = Val(Mid(ind, i)) 
    End If 
    St = St + Chr(Mult(CLng(tok), d, n)) 
    If Not nxt = 0 Then 
        i = nxt 
    Else 
        i = Len(ind) 
    End If 
Next i 
Decode = St 
End Function 

' To Be Continue... 

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