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📄 lstconcat.c

📁 早期freebsd实现
💻 C
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/* * Copyright (c) 1988, 1989, 1990, 1993 *	The Regents of the University of California.  All rights reserved. * * This code is derived from software contributed to Berkeley by * Adam de Boor. * * Redistribution and use in source and binary forms, with or without * modification, are permitted provided that the following conditions * are met: * 1. Redistributions of source code must retain the above copyright *    notice, this list of conditions and the following disclaimer. * 2. Redistributions in binary form must reproduce the above copyright *    notice, this list of conditions and the following disclaimer in the *    documentation and/or other materials provided with the distribution. * 3. All advertising materials mentioning features or use of this software *    must display the following acknowledgement: *	This product includes software developed by the University of *	California, Berkeley and its contributors. * 4. Neither the name of the University nor the names of its contributors *    may be used to endorse or promote products derived from this software *    without specific prior written permission. * * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF * SUCH DAMAGE. */#ifndef lintstatic char sccsid[] = "@(#)lstConcat.c	8.1 (Berkeley) 6/6/93";#endif /* not lint *//*- * listConcat.c -- *	Function to concatentate two lists. */#include    "lstInt.h"/*- *----------------------------------------------------------------------- * Lst_Concat -- *	Concatenate two lists. New elements are created to hold the data *	elements, if specified, but the elements themselves are not copied. *	If the elements should be duplicated to avoid confusion with another *	list, the Lst_Duplicate function should be called first. *	If LST_CONCLINK is specified, the second list is destroyed since *	its pointers have been corrupted and the list is no longer useable. * * Results: *	SUCCESS if all went well. FAILURE otherwise. * * Side Effects: *	New elements are created and appended the the first list. *----------------------------------------------------------------------- */ReturnStatusLst_Concat (l1, l2, flags)    Lst    	  	l1; 	/* The list to which l2 is to be appended */    Lst    	  	l2; 	/* The list to append to l1 */    int	   	  	flags;  /* LST_CONCNEW if LstNode's should be duplicated				 * LST_CONCLINK if should just be relinked */{    register ListNode  	ln;     /* original LstNode */    register ListNode  	nln;    /* new LstNode */    register ListNode  	last;   /* the last element in the list. Keeps				 * bookkeeping until the end */    register List 	list1 = (List)l1;    register List 	list2 = (List)l2;    if (!LstValid (l1) || !LstValid (l2)) {	return (FAILURE);    }    if (flags == LST_CONCLINK) {	if (list2->firstPtr != NilListNode) {	    /*	     * We set the nextPtr of the	     * last element of list two to be NIL to make the loop easier and	     * so we don't need an extra case should the first list turn	     * out to be non-circular -- the final element will already point	     * to NIL space and the first element will be untouched if it	     * existed before and will also point to NIL space if it didn't.	     */	    list2->lastPtr->nextPtr = NilListNode;	    /*	     * So long as the second list isn't empty, we just link the	     * first element of the second list to the last element of the	     * first list. If the first list isn't empty, we then link the	     * last element of the list to the first element of the second list	     * The last element of the second list, if it exists, then becomes	     * the last element of the first list.	     */	    list2->firstPtr->prevPtr = list1->lastPtr;	    if (list1->lastPtr != NilListNode) { 		list1->lastPtr->nextPtr = list2->firstPtr;	    }	    list1->lastPtr = list2->lastPtr;	}	if (list1->isCirc && list1->firstPtr != NilListNode) {	    /*	     * If the first list is supposed to be circular and it is (now)	     * non-empty, we must make sure it's circular by linking the	     * first element to the last and vice versa	     */	    list1->firstPtr->prevPtr = list1->lastPtr;	    list1->lastPtr->nextPtr = list1->firstPtr;	}	free ((Address)l2);    } else if (list2->firstPtr != NilListNode) {	/*	 * We set the nextPtr of the last element of list 2 to be nil to make	 * the loop less difficult. The loop simply goes through the entire	 * second list creating new LstNodes and filling in the nextPtr, and	 * prevPtr to fit into l1 and its datum field from the	 * datum field of the corresponding element in l2. The 'last' node	 * follows the last of the new nodes along until the entire l2 has	 * been appended. Only then does the bookkeeping catch up with the	 * changes. During the first iteration of the loop, if 'last' is nil,	 * the first list must have been empty so the newly-created node is	 * made the first node of the list.	 */	list2->lastPtr->nextPtr = NilListNode;	for (last = list1->lastPtr, ln = list2->firstPtr;	     ln != NilListNode;	     ln = ln->nextPtr)	{	    PAlloc (nln, ListNode);	    nln->datum = ln->datum;	    if (last != NilListNode) {		last->nextPtr = nln;	    } else {		list1->firstPtr = nln;	    }	    nln->prevPtr = last;	    nln->flags = nln->useCount = 0;	    last = nln;	}	/*	 * Finish bookkeeping. The last new element becomes the last element	 * of list one. 	 */	list1->lastPtr = last;	/*	 * The circularity of both list one and list two must be corrected	 * for -- list one because of the new nodes added to it; list two	 * because of the alteration of list2->lastPtr's nextPtr to ease the	 * above for loop.	 */	if (list1->isCirc) {	    list1->lastPtr->nextPtr = list1->firstPtr;	    list1->firstPtr->prevPtr = list1->lastPtr;	} else {	    last->nextPtr = NilListNode;	}	if (list2->isCirc) {	    list2->lastPtr->nextPtr = list2->firstPtr;	}    }    return (SUCCESS);}	

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