⭐ 欢迎来到虫虫下载站! | 📦 资源下载 📁 资源专辑 ℹ️ 关于我们
⭐ 虫虫下载站

📄 scroll.c

📁 早期freebsd实现
💻 C
📖 第 1 页 / 共 2 页
字号:
/* Calculate what ins/del line to do, and do it, for Emacs redisplay.   Copyright (C) 1985, 1986, 1990 Free Software Foundation, Inc.This file is part of GNU Emacs.GNU Emacs is free software; you can redistribute it and/or modifyit under the terms of the GNU General Public License as published bythe Free Software Foundation; either version 1, or (at your option)any later version.GNU Emacs is distributed in the hope that it will be useful,but WITHOUT ANY WARRANTY; without even the implied warranty ofMERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See theGNU General Public License for more details.You should have received a copy of the GNU General Public Licensealong with GNU Emacs; see the file COPYING.  If not, write tothe Free Software Foundation, 675 Mass Ave, Cambridge, MA 02139, USA.  */#include <stdio.h>#include "config.h"#include "termchar.h"#include "termhooks.h"#include "dispextern.h"#define max(a, b) ((a) > (b) ? (a) : (b))#define min(a, b) ((a) < (b) ? (a) : (b))struct matrix_elt  {    /* Cost of outputting through this line       if no insert/delete is done just above it.  */    int writecost;    /* Cost of outputting through this line       if an insert is done just above it.  */    int insertcost;    /* Cost of outputting through this line       if a delete is done just above it.  */    int deletecost;    /* Number of inserts so far in this run of inserts,       for the cost in insertcost.  */    char insertcount;    /* Number of deletes so far in this run of deletes,       for the cost in deletecost.  */    char deletecount;  };/* This exceeds the sum of any reasonable number of INFINITY's.  */#define SUPER_INFINITY (1000 * INFINITY)/* See CalcIDCosts for on the arrays below */int *ILcost;int *DLcost;int *ILncost;int *DLncost;scrolling_1 (window_size, unchanged_at_top, unchanged_at_bottom,	     draw_cost, old_hash, new_hash, free_at_end)     int window_size, unchanged_at_top, unchanged_at_bottom;     int *draw_cost;     int *old_hash;     int *new_hash;     int free_at_end;{  struct matrix_elt *matrix;  matrix = ((struct matrix_elt *)	    alloca ((window_size + 1) * (window_size + 1) * sizeof *matrix));  calculate_scrolling (matrix, window_size, unchanged_at_bottom,		       draw_cost, old_hash, new_hash,		       free_at_end);  do_scrolling (matrix, window_size, unchanged_at_top);}/* Determine, in matrix[i,j], the cost of updating the first j old lines   into the first i new lines.   This involves using insert or delete somewhere if i != j.   For each matrix elements, three kinds of costs are recorded:   the smallest cost that ends with an insert, the smallest   cost that ends with a delete, and the smallest cost that   ends with neither one.  These are kept separate because   on some terminals the cost of doing an insert varies   depending on whether one was just done, etc.  *//* draw_cost[VPOS] is the cost of outputting new line at VPOS.   old_hash[VPOS] is the hash code of the old line at VPOS.   new_hash[VPOS] is the hash code of the new line at VPOS.   Note that these are not true screen vpos's, but relative   to the place at which the first mismatch between old and   new contents appears.  */calculate_scrolling (matrix, window_size, lines_below,		     draw_cost, old_hash, new_hash,		     free_at_end)     /* matrix is of size window_size + 1 on each side.  */     struct matrix_elt *matrix;     int window_size;     int *draw_cost;     int *old_hash;     int *new_hash;     int free_at_end;{  register int i, j;  register struct matrix_elt *p, *p1;  register int cost, cost1;  int lines_moved = window_size + (scroll_region_ok ? 0 : lines_below);  /* We subtract 1 to compensate for the fact that i and j have values     starting with 1.  */  int *first_insert_cost = &ILcost[screen_height - lines_moved - 1];  int *first_delete_cost = &DLcost[screen_height - lines_moved - 1];  int *next_insert_cost = &ILncost[screen_height - lines_moved - 1];  int *next_delete_cost = &DLncost[screen_height - lines_moved - 1];  /* initialize the top left corner of the matrix */  matrix->writecost = 0;  matrix->insertcost = SUPER_INFINITY;  matrix->deletecost = SUPER_INFINITY;  matrix->insertcount = 0;  matrix->deletecount = 0;  /* initialize the left edge of the matrix */  cost = first_insert_cost[1] - next_insert_cost[1];  for (i = 1; i <= window_size; i++)    {      p = matrix + i * (window_size + 1);      cost += draw_cost[i] + next_insert_cost[i];      p->insertcost = cost;      p->writecost = SUPER_INFINITY;      p->deletecost = SUPER_INFINITY;      p->insertcount = i;      p->deletecount = 0;    }  /* initialize the top edge of the matrix */  cost = first_delete_cost[1] - next_delete_cost[1];  for (j = 1; j <= window_size; j++)    {      cost += next_delete_cost[j];      matrix[j].deletecost = cost;      matrix[j].writecost = SUPER_INFINITY;      matrix[j].insertcost = SUPER_INFINITY;      matrix[j].deletecount = j;      matrix[j].insertcount = 0;    }  /* `i' represents the vpos among new screen contents.     `j' represents the vpos among the old screen contents.  */  p = matrix + window_size + 2;	/* matrix [1, 1] */  for (i = 1; i <= window_size; i++, p++)    for (j = 1; j <= window_size; j++, p++)      {	/* p contains the address of matrix [i, j] */	/* First calculate the cost assuming we do	   not insert or delete above this line.	   That is, if we update through line i-1	   based on old lines through j-1,	   and then just change old line j to new line i.  */	p1 = p - window_size - 2; /* matrix [i-1, j-1] */	cost = p1->writecost;	if (cost > p1->insertcost)	  cost = p1->insertcost;	if (cost > p1->deletecost)	  cost = p1->deletecost;	if (old_hash[j] != new_hash[i])	  cost += draw_cost[i];	p->writecost = cost;	/* Calculate the cost if we do an insert-line	   before outputting this line.	   That is, we update through line i-1	   based on old lines through j,	   do an insert-line on line i,	   and then output line i from scratch,	   leaving old lines starting from j for reuse below.  */	p1 = p - window_size - 1; /* matrix [i-1, j] */	/* No need to think about doing a delete followed	   immediately by an insert.  It cannot be as good	   as not doing either of them.  */	if (free_at_end == i)	  {	    cost = p1->writecost;	    cost1 = p1->insertcost;	  }	else	  {	    cost = p1->writecost + first_insert_cost[i];	    if (p1->insertcount > i)	      abort ();	    cost1 = p1->insertcost + next_insert_cost[i - p1->insertcount];	  }	p->insertcost = min (cost, cost1) + draw_cost[i];	p->insertcount = (cost < cost1) ? 1 : p1->insertcount + 1;	if (p->insertcount > i)	  abort ();	/* Calculate the cost if we do a delete line after	   outputting this line.	   That is, we update through line i	   based on old lines through j-1,	   and throw away old line j.  */	p1 = p - 1;		/* matrix [i, j-1] */	/* No need to think about doing an insert followed	   immediately by a delete.  */	if (free_at_end == i)	  {	    cost = p1->writecost;	    cost1 = p1->deletecost;	  }	else	  {	    cost = p1->writecost + first_delete_cost[i];	    cost1 = p1->deletecost + next_delete_cost[i];	  }	p->deletecost = min (cost, cost1);	p->deletecount = (cost < cost1) ? 1 : p1->deletecount + 1;      }}/* Perform insert-lines and delete-lines operations according to the costs in the matrix. Updates the contents of current_screen to record what was done. */do_scrolling (matrix, window_size, unchanged_at_top)     struct matrix_elt *matrix;     int window_size;     int unchanged_at_top;{  register struct matrix_elt *p;  register int i, j;  struct queue { int count, pos; } *queue;  int offset = unchanged_at_top;  int qi = 0;  int window = 0;  register int tem;  int next;  queue = (struct queue *) alloca (screen_height * sizeof (struct queue));  bcopy (current_screen->contents, temp_screen->contents,	 current_screen->height * sizeof (char *));  bcopy (current_screen->used, temp_screen->used,	 current_screen->height * sizeof (int));  bcopy (current_screen->highlight, temp_screen->highlight,	 current_screen->height);  bzero (temp_screen->enable, temp_screen->height);/* First do all deletions of lines; queue up insertions.   Also move lines to correct slots in current_screen.  */  i = j = window_size;

⌨️ 快捷键说明

复制代码 Ctrl + C
搜索代码 Ctrl + F
全屏模式 F11
切换主题 Ctrl + Shift + D
显示快捷键 ?
增大字号 Ctrl + =
减小字号 Ctrl + -