📄 median.awk
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#!/bin/awk -f## Copyright (c) 1990, 1993# The Regents of the University of California. All rights reserved.## This code is derived from software contributed to Berkeley by# Van Jacobson.## Redistribution and use in source and binary forms, with or without# modification, are permitted provided that the following conditions# are met:# 1. Redistributions of source code must retain the above copyright# notice, this list of conditions and the following disclaimer.# 2. Redistributions in binary form must reproduce the above copyright# notice, this list of conditions and the following disclaimer in the# documentation and/or other materials provided with the distribution.# 3. All advertising materials mentioning features or use of this software# must display the following acknowledgement:# This product includes software developed by the University of# California, Berkeley and its contributors.# 4. Neither the name of the University nor the names of its contributors# may be used to endorse or promote products derived from this software# without specific prior written permission.## THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND# ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE# IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE# ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE# FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL# DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS# OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)# HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT# LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY# OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF# SUCH DAMAGE.## @(#)median.awk 8.1 (Berkeley) 6/6/93#/^ *[0-9]/ { # print out the median time to each hop along a route. tottime = 0; n = 0; for (f = 5; f <= NF; ++f) { if ($f == "ms") { ++n time[n] = $(f - 1) } } if (n > 0) { # insertion sort the times to find the median for (i = 2; i <= n; ++i) { v = time[i]; j = i - 1; while (time[j] > v) { time[j+1] = time[j]; j = j - 1; if (j < 0) break; } time[j+1] = v; } if (n > 1 && (n % 2) == 0) median = (time[n/2] + time[(n/2) + 1]) / 2 else median = time[(n+1)/2] print $1, median }}
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