📄 call.out
字号:
reading symbolic information ...startingprintf returns successfully[2] stop at 15[2] stopped in main at line 15 15 p1();in p1p1 returns successfullyin p2(3)p2 returns successfullyin p3(blah)p3 returns successfullymain_local = 19printf returns successfully19 call call ^ syntax error"call" not call-abletoo many parameters in call to p1type mismatch for from_main in call to p2[8] stop in p3[8] stopped in p3 at line 36 36 printf("in p3(%s)\n", s);in p3(blah)p3 returns successfullymain(argc = 1, argv = 0x7fffebe8, 0x7fffebf0), line 15 in "call.c"
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -