myasm1.asm

8位微程序控制计算机设计实验 汇编控制CPU简单乘法

ORG 0

STRT:
JKB STRT
LDA 8001H
MOV R0,A; ----------------------------------------------被乘数a送R0

L1:
JKB L1
LDA 8001H
mov R1,A; ----------------------------------------------乘数b送R1
MOV A,#1
STA 8002H;---------------------------------------------打印“x”

L2:
JPB L2
MOV A,#0AH
STA 8002H;---------------------------------------------打印空格

L3:
JPB L3
MOV A,#10H
ADD A,R0
STA 8002H;---------------------------------------------打印a后换行

L4:
JPB L4
MOV A,#9
STA 8002H;---------------------------------------------打印“＝”

L5:
JPB L5
MOV A,#0AH
STA 8002H;---------------------------------------------打印空格

L6:
JPB L6
MOV A,#10H
ADD A,R1
STA 8002H;--------------------------------------------打印b后换行

L7:
JPB L7
MOV A,#0AH
STA 8002H;--------------------------------------------打印空格

L8:
JPB L8
MOV A,#0AH
STA 8002H;--------------------------------------------打印空格

L9:
MOV A,R0
MOV R3,A; a送R3
MOV A,R1
MOV R2,#1
SUB A,R2
MOV R1,A;---------------------------------------------b -1

L10:
MOV A,R3
ADD A,R0
MOV R3,A;---------------------------------------------- a+a
MOV A,R1
SUB A,R2;---------------------------------------------- b-1
MOV R1,A
JC OVER; ---------------------------------------------- 如产生借位，需恢复
JMP L10

L11:
MOV R4,#0;--------------------------------------------计数器R4清零

L12:
MOV A,R4
ADD A,R2; ---------------------------------------------R2中的数是1
MOV R4,A;--------------------------------------------- 计数器R4增1
MOV A,R3
MOV R5,#10H
SUB A,R5;--------------------------------------------- 结果高4位减1
MOV R3,A
JC OVER2
JMP L12

L13:
JPB L13
MOV A,R3
STA 8002H;----------------------------------------- 打印结果低4位

L14:
JPB L14
MOV A,#10H
ADD A,R4
STA 8002H; ---------------------------------------打印结果高4位

OUT:
STA 8002H

L15:
JPB L15
JMP STRT

OVER:
MOV A,R3
SUB A,R0
MOV R3,A;  ----------------------------------------产生8位结果，送R3
JMP L11

OVER2:
MOV A,R4
SUB A,R2;----------------------------------------  计数器减1
MOV R4,A
MOV A,R3
ADD A,R5
MOV R3,A; ---------------------------------------- R3保存结果低4位
JMP L13