📄 民212.m
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if c3<=bb/2 && c4<=bb/2
ept1=hanp(1,n2);
eptj1=liep(1,n2);
spt1=hanpi(1,n1);
sptj1=lienj(1,n1);
tkk4=0;
ept2=ept1+1;eptj2=eptj1-1;
while (A(ept2,eptj2)>0||A(ept2,eptj1)>0||A(ept1,eptj2)>0)&&(ept2<spt1)&&(eptj2>sptj1)
tkk4=tkk4+1;
ept2=ept2+1;
eptj2=eptj2-1;
end
end
if tkk4>2
k5=k5+1;
BBBBp(1,k5)=n2;%%%%%%%%%%%撇的终点将撇的终点与撇的起点联系起来
AAAAp(1,k5)=n1;
ent1=hanp(1,n2);
ent1j=liep(1,n2);
snt1=hanni(1,n1);
sntj1=liepj(1,n1);
tkk4=0;
if (A(ent1+1,ent1j)>0||A(ent1,ent1j-1)>0||A(ent1+1,ent1j-1)>0)
kk4=tkk4+1;
ent1=ent1+1;
ent1j=ent1j-1;
while A(ent1,ent1j)>0&&(ent1<=snt1)&&(ent1j>=sntj1)
tkk4=tkk4+1;
ent1=ent1+1;
ent1j=ent1j-1;
end
end
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