e454. listing the contents of a zip file.txt

这里面包含了一百多个JAVA源文件

try {
        // Open the ZIP file
        ZipFile zf = new ZipFile("filename.zip");
    
        // Enumerate each entry
        for (Enumeration entries = zf.entries(); entries.hasMoreElements();) {
            // Get the entry name
            String zipEntryName = ((ZipEntry)entries.nextElement()).getName();
        }
    } catch (IOException e) {
    }