📄 test1.c
字号:
#include "mpi.h" #include "stdio.h"/* tests a series of puts, gets, and accumulate on 2 processes */#define SIZE 10int main(int argc, char *argv[]) { int rank, nprocs, A[SIZE], B[SIZE], i; MPI_Win win; MPI_Init(&argc,&argv); MPI_Comm_size(MPI_COMM_WORLD,&nprocs); MPI_Comm_rank(MPI_COMM_WORLD,&rank); if (nprocs != 2) { printf("Run this program with 2 processes\n"); MPI_Abort(MPI_COMM_WORLD,1); } if (rank == 0) { for (i=0; i<SIZE; i++) A[i] = B[i] = i; } else { for (i=0; i<SIZE; i++) { A[i] = (-3)*i; B[i] = (-4)*i; } } MPI_Win_create(B, SIZE*sizeof(int), sizeof(int), MPI_INFO_NULL, MPI_COMM_WORLD, &win); MPI_Win_fence(0, win); if (rank == 0) { for (i=0; i<SIZE-1; i++) MPI_Put(A+i, 1, MPI_INT, 1, i, 1, MPI_INT, win); } else { for (i=0; i<SIZE-1; i++) MPI_Get(A+i, 1, MPI_INT, 0, i, 1, MPI_INT, win); MPI_Accumulate(A+i, 1, MPI_INT, 0, i, 1, MPI_INT, MPI_SUM, win); } MPI_Win_fence(0, win); if (rank == 1) { for (i=0; i<SIZE-1; i++) { if (A[i] != B[i]) printf("Put/Get Error: A[i]=%d, B[i]=%d\n", A[i], B[i]); } } else { if (B[SIZE-1] != SIZE - 1 - 3*(SIZE-1)) printf("Accumulate Error: B[SIZE-1] is %d, should be %d\n", B[SIZE-1], SIZE - 1 - 3*(SIZE-1)); } MPI_Win_free(&win); if (rank==0) printf("Done\n"); MPI_Finalize(); return 0; }
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -