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<P><FONT color=#000000
size=2>24点计算</FONT></P></TD></TR></TBODY></TABLE></TD></TR>
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<P>/*a20.c*/<BR>#include<stdio.h><BR>main()<BR>{<BR>int
a[4],m,n,x,y,b,c,d,tt;<BR>float u,i,p;<BR>tt=0;<BR>scanf("%d
%d %d
%d",&a[0],&a[1],&a[2],&a[3]);<BR>for(m=0;m<4;m++)<BR>for(n=0;n<4;n++)<BR>for(x=0;x<4;x++)<BR>for(y=0;y<4;y++){<BR>if(m!=n&&m!=x&&m!=y&&n!=x&&n!=y&&x!=y)<BR>{<BR>for(b=0;b<4;b++)<BR>for(c=0;c<4;c++)<BR>for(d=0;d<4;d++)<BR>{<BR>if(b==0)
u=a[m]+a[n];<BR>if(b==1) u=a[m]-a[n];<BR>if(b==2)
u=a[m]*a[n];<BR>if(b==3)
u=(float)a[m]/(float)a[n];<BR>if(c==0) i=u+a[x];<BR>if(c==1)
i=u-a[x];<BR>if(c==2) i=u*a[x];<BR>if(c==3)
i=u/(float)a[x];<BR>if(d==0) p=i+a[y];<BR>if(d==1)
p=i-a[y];<BR>if(d==2) p=i*a[y];<BR>if(d==3)
p=i/(float)a[y];<BR>if(p==24.0)<BR>{<BR>tt=1;<BR>printf("%d",a[m]);<BR>if(b==0)
printf("+");<BR>if(b==1) printf("-");<BR>if(b==2)
printf("*");<BR>if(b==3)
printf("/");<BR>printf("%d",a[n]);<BR>if(c==0)
printf("+");<BR>if(c==1) printf("-");<BR>if(c==2)
printf("*");<BR>if(c==3)
printf("/");<BR>printf("%d",a[x]);<BR>if(d==0)
printf("+");<BR>if(d==1) printf("-");<BR>if(d==2)
printf("*");<BR>if(d==3)
printf("/");<BR>printf("%d\n",a[y]);<BR>}<BR>}<BR>}<BR>}<BR>if(tt==0)
printf("bu ke nen\n");<BR>}</P></TD></TR></TBODY></TABLE>
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