9-27.txt

C++完美演绎源代码

/* 范例：9-27 */
#include <stdio.h>
#include <stdlib.h>
void main(int argc,int *argv[])
{
  FILE *fp1,*fp2;
  int ch,ret;

  if(argc!=3)
  {
    printf("Syntax Error!\n\tp9-27 source target");
    exit(1);
  }
  fp1=fopen(argv[1],"rb");
  fp2=fopen(argv[2],"wb");
  while(!feof(fp1))
  {
    ch = getc(fp1);
    if(ch!=EOF)
      putc(ch,fp2);
  }

  fclose(fp1);
  fclose(fp2);
}

程序执行结果：(假设要把oo.txt复制成xx.txt)
D:\TC>p9-27 oo.txt xx.txt