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📄 mpsqrt.c

📁 Glibc 2.3.2源代码(解压后有100多M)
💻 C
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/* * IBM Accurate Mathematical Library * written by International Business Machines Corp. * Copyright (C) 2001 Free Software Foundation * * This program is free software; you can redistribute it and/or modify * it under the terms of the GNU Lesser General Public License as published by * the Free Software Foundation; either version 2.1 of the License, or * (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the * GNU Lesser General Public License for more details. * * You should have received a copy of the GNU Lesser General Public License * along with this program; if not, write to the Free Software * Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA. *//****************************************************************************//*  MODULE_NAME:mpsqrt.c                                                    *//*                                                                          *//*  FUNCTION:mpsqrt                                                         *//*           fastiroot                                                      *//*                                                                          *//* FILES NEEDED:endian.h mpa.h mpsqrt.h                                     *//*              mpa.c                                                       *//* Multi-Precision square root function subroutine for precision p >= 4.    *//* The relative error is bounded by 3.501*r**(1-p), where r=2**24.          *//*                                                                          *//****************************************************************************/#include "endian.h"#include "mpa.h"/****************************************************************************//* Multi-Precision square root function subroutine for precision p >= 4.    *//* The relative error is bounded by 3.501*r**(1-p), where r=2**24.          *//* Routine receives two pointers to  Multi Precision numbers:               *//* x (left argument) and y (next argument). Routine also receives precision *//* p as integer. Routine computes sqrt(*x) and stores result in *y          *//****************************************************************************/double fastiroot(double);void __mpsqrt(mp_no *x, mp_no *y, int p) {#include "mpsqrt.h"  int i,m,ex,ey;  double dx,dy;  mp_no    mphalf   = {0,{0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,                   0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,                   0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0}},    mp3halfs = {0,{0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,                   0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,                   0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0}};  mp_no mpxn,mpz,mpu,mpt1,mpt2;  /* Prepare multi-precision 1/2 and 3/2 */  mphalf.e  =0;  mphalf.d[0]  =ONE;  mphalf.d[1]  =HALFRAD;  mp3halfs.e=1;  mp3halfs.d[0]=ONE;  mp3halfs.d[1]=ONE;  mp3halfs.d[2]=HALFRAD;  ex=EX;      ey=EX/2;     __cpy(x,&mpxn,p);    mpxn.e -= (ey+ey);  __mp_dbl(&mpxn,&dx,p);   dy=fastiroot(dx);    __dbl_mp(dy,&mpu,p);  __mul(&mpxn,&mphalf,&mpz,p);  m=mp[p];  for (i=0; i<m; i++) {    __mul(&mpu,&mpu,&mpt1,p);    __mul(&mpt1,&mpz,&mpt2,p);    __sub(&mp3halfs,&mpt2,&mpt1,p);    __mul(&mpu,&mpt1,&mpt2,p);    __cpy(&mpt2,&mpu,p);  }  __mul(&mpxn,&mpu,y,p);  EY += ey;  return;}/***********************************************************//* Compute a double precision approximation for 1/sqrt(x)  *//* with the relative error bounded by 2**-51.              *//***********************************************************/double fastiroot(double x) {  union {long i[2]; double d;} p,q;  double y,z, t;  long n;  static const double c0 = 0.99674, c1 = -0.53380, c2 = 0.45472, c3 = -0.21553;  p.d = x;  p.i[HIGH_HALF] = (p.i[HIGH_HALF] & 0x3FFFFFFF ) | 0x3FE00000 ;  q.d = x;  y = p.d;  z = y -1.0;  n = (q.i[HIGH_HALF] - p.i[HIGH_HALF])>>1;  z = ((c3*z + c2)*z + c1)*z + c0;            /* 2**-7         */  z = z*(1.5 - 0.5*y*z*z);                    /* 2**-14        */  p.d = z*(1.5 - 0.5*y*z*z);                  /* 2**-28        */  p.i[HIGH_HALF] -= n;  t = x*p.d;  return p.d*(1.5 - 0.5*p.d*t);}

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