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📄 e_powf.s

📁 Glibc 2.3.2源代码(解压后有100多M)
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          nop.i 999}{ .mfi          nop.m 999          fma.s1 POW_f12                     = POW_f1, POW_f2,f0          nop.i 999};;{ .mfi          nop.f 999(p9)      cmp.le.unc p0,p10                  = 6, pow_GR_true_exp_Y_Gpr};;{ .mfb          nop.m 999          fma.s1 POW_e123                    = POW_e12, f1, POW_e3(p8)      br.cond.spnt L(POW_OVER_UNDER_X_NOT_INF)};;{ .mmf          fma.s1 POW_q                       = POW_Z3sq, POW_q, POW_Z3};;{ .mfi          nop.m 999           fma.s1 POW_ssq                     = POW_s, POW_s, f0          nop.i 999}{ .mfi          nop.m 999           fma.s1 POW_v4                      = POW_s, POW_Q3, POW_Q2          nop.i 999};;{ .mfi          nop.m 999          fma.s1 POW_v2                      = POW_s, POW_Q1, POW_Q0_half          nop.i 999}{ .mfi          nop.m 999          fma.s1 POW_1ps                     = f1,f1,POW_s          nop.i 999};;{ .mfi          nop.m 999          fma.s1 POW_f3                      = POW_e123,f1,f1          nop.i 999};;{ .mfi          nop.m 999          fma.s1 POW_T1T2                    = POW_T1, POW_T2, f0          nop.i 999};;{ .mfi          nop.m 999          fma.s1 POW_v3                     = POW_ssq, POW_Q4, POW_v4          nop.i 999};;{ .mfi          nop.m 999          fma.s1 POW_v21ps                  = POW_ssq, POW_v2, POW_1ps          nop.i 999}{ .mfi          nop.m 999          fma.s1 POW_s4                     = POW_ssq, POW_ssq, f0          nop.i 999};;{ .mfi          nop.m 999          fma.s1 POW_f123                    = POW_f12, POW_f3, f0          nop.i 999};;{ .mfi          nop.m 999          fma.s1 POW_A                      =  POW_2M, POW_T1T2, f0          nop.i 999};;{ .mfi          nop.m 999(p12)     fmerge.s POW_f123 = f8,POW_f123  // if x neg, y odd int          nop.i 999}{ .mfi          nop.m 999//          fma.s1 POW_es                     = POW_ssq,  POW_v3, POW_v2          nop.i 999};;{ .mfi          nop.m 999          fma.s1 POW_es                     = POW_s4,  POW_v3, POW_v21ps          nop.i 999};;{ .mfi          nop.m 999          fma.s1 POW_A                      = POW_A, POW_f123, f0          nop.i 999}{ .mfi          nop.m 999//          fma.s1 POW_es                     = POW_es, POW_ssq, POW_1ps          nop.i 999};;{ .mfi          nop.m 999          fma.s1 POW_A                      = POW_A, POW_es,f0          nop.i 999};;{ .mfb          nop.m 999(p10)     fma.s f8                          = POW_A, POW_q, POW_A(p10)     br.ret.sptk     b0};;// POSSIBLE_OVER_UNDER// p6 = TRUE ==> Y negative{ .mfi        nop.m 999        fmerge.s POW_abs_A                = f0, POW_A        cmp.eq.unc p0,p6                  = pow_GR_sign_Y, r0};;{ .mib        nop.m 999        nop.i 999(p6)    br.cond.spnt L(POW_POSSIBLE_UNDER) };;// POSSIBLE_OVER// We got an answer. // overflow is a possibility, not a certainty// We define an overflow when the answer with//    WRE set//    user-defined rounding mode// double// Largest double is 7FE (biased double)//                   7FE - 3FF + FFFF = 103FE// Create + largest_double_plus_ulp// Create - largest_double_plus_ulp// Calculate answer with WRE set.// single// Largest single is FE (biased double)//                   FE - 7F + FFFF = 1007E// Create + largest_single_plus_ulp// Create - largest_single_plus_ulp// Calculate answer with WRE set.// Cases when answer is ldn+1  are as follows://  ldn                   ldn+1// --+----------|----------+------------//              |//    +inf          +inf      -inf//                  RN         RN//                             RZ// Put in s2 (td set, wre set){ .mfi        mov           pow_GR_gt_ln                 = 0x1007f         fsetc.s2 0x7F,0x42        nop.i 999 };;{ .mfi        setf.exp POW_gt_pln                        = pow_GR_gt_ln        fma.s.s2 POW_wre_urm_f8                    = POW_abs_A, POW_q, POW_abs_A        nop.i 999 ;;}// Return s2 to default{ .mfi        nop.m 999        fsetc.s2 0x7F,0x40        nop.i 999};;// p7 = TRUE ==> yes, we have an overflow{ .mfi        nop.m 999        fcmp.ge.unc.s1 p7, p0                    =  POW_wre_urm_f8, POW_gt_pln        nop.i 999};;{ .mfb(p7)   mov pow_GR_tag                            = 30       fma.s f8                                  = POW_A, POW_q, POW_A(p7)   br.cond.spnt __libm_error_region }{ .mfb       nop.m 999       nop.f 999(p0)   br.ret.sptk     b0 };;L(POW_POSSIBLE_UNDER):// We got an answer. input was < -2^9 but > -2^10 (double)// We got an answer. input was < -2^6 but > -2^7  (float)// underflow is a possibility, not a certainty// We define an underflow when the answer with//    ftz set// is zero (tiny numbers become zero)// Notice (from below) that if we have an unlimited exponent range,// then there is an extra machine number E between the largest denormal and// the smallest normal.// So if with unbounded exponent we round to E or below, then we are// tiny and underflow has occurred.// But notice that you can be in a situation where we are tiny, namely// rounded to E, but when the exponent is bounded we round to smallest// normal. So the answer can be the smallest normal with underflow.//                           E// -----+--------------------+--------------------+-----//      |                    |                    |//   1.1...10 2^-3fff    1.1...11 2^-3fff    1.0...00 2^-3ffe//   0.1...11 2^-3ffe                                   (biased, 1)//    largest dn                               smallest normal// Put in s2 (td set, ftz set){ .mfi        nop.m 999        fsetc.s2 0x7F,0x41        nop.i 999 };;{ .mfi        nop.m 999        fma.s.s2 POW_ftz_urm_f8                    = POW_A, POW_q, POW_A        nop.i 999};;// Return s2 to default{ .mfi        nop.m 999        fsetc.s2 0x7F,0x40        nop.i 999 };;// p7 = TRUE ==> yes, we have an underflow{ .mfi        nop.m 999        fcmp.eq.unc.s1 p7, p0                     =  POW_ftz_urm_f8, f0        nop.i 999 };;{ .mfb(p7)    mov pow_GR_tag                           = 31        fma.s f8                                 = POW_A, POW_q, POW_A(p7)    br.cond.spnt __libm_error_region };;{ .mfb        nop.m 999        nop.f 999        br.ret.sptk     b0 };;L(POW_X_DENORM):// Here if x unorm. Use the NORM_X for getf instructions, and the back// to normal path{ .mfi        getf.exp      pow_GR_signexp_X    = POW_NORM_X        nop.f 999        nop.i 999};;{ .mfi        getf.sig      pow_GR_sig_X        = POW_NORM_X        nop.f 999        nop.i 999};;{ .mfi        and           pow_GR_exp_X        = pow_GR_signexp_X, pow_GR_17ones        nop.f 999};;{ .mib        sub       pow_GR_true_exp_X       = pow_GR_exp_X, pow_GR_16ones        shl           pow_GR_offset       = pow_GR_sig_X, 1        br.cond.sptk    L(POW_COMMON)};;L(POW_X_0_Y_0):// When X is +-0 and Y is +-0, IEEE returns 1.0 // We call error support with this value { .mfb         mov pow_GR_tag                     = 32         fma.s f8                           = f1,f1,f0         br.cond.sptk __

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