📄 5_6.c
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/*求ax^ +bx + c = 0的方程的解.
a = 0 ,不是二次方程;
b^ -4ac = 0,有两个相等实根;
b^ -4ac > 0,有两个不等实根;
b^ -4ac < 0,有两个共厄复根;
*/
# include <math.h>
# include <stdio.h>
main()
{ printf("请输入二次方程的a,b,c.它们在方程式中的含义这样的:ax^ + bx + c = 0 \n");
printf("输入abc的时候,用逗号分隔!!!!\n");
float a,b,c,d,disc,x1,x2,realpart,imagpart;
if (scanf("%f,%f,%f",&a,&b,&c)<=0) {
printf("非法输入");
//return -1;
exit();
}
printf("The equation ");
disc = b*b-4*a*c;
if (fabs(a)<=1e-6) printf("is not a quadratic");
else if (fabs(disc) <= 1e-6) printf("has two equal roots:%8.4\n",-b/(2*a));
else if (disc>1e-6) {
x1 = (-b + sqrt(disc))/(2*a);
x2 = (-b - sqrt(disc))/(2*a);
printf("has two distinct real roots:%8.4f and %8.4f\n",x1,x2);
}
else {
realpart = -b/(2*a);
imagpart = sqrt(-disc)/(2*a);
printf("has complex roots:\n");
printf("%8.4f + %8.4fi\n",realpart,imagpart);
printf("%8.4f - %8.4fi\n",realpart,imagpart);
}
}
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